A leap year consists of 366 days.
52 weeks + 2 days.
These 2 days can be: (mon,tue),(tue,wed),(wed,thu),(thu,fri),(fri,sat)(sat,sun)(sun,mon)
Thus, the total number of cases = 7.
The number of cases in which we get Friday = 2(Thu, Fri)(Fri, Sat).
Therefore the required probability = 2/7.
Answer:
18
Step-by-step explanation:
108
I'm not positive but i belive this is correct
C. The number of times a dessert was offered at a special price.
9514 1404 393
300 g
The problem statement tells us ...
36g = 0.12×d . . . . . where d represents the daily value
36g/0.12 = d = 300g . . . . divide by the coefficient of d
300 g of carbohydrates per day are recommended.
Here’s what I got for this worksheet.
