A leap year consists of 366 days.
52 weeks + 2 days.
These 2 days can be: (mon,tue),(tue,wed),(wed,thu),(thu,fri),(fri,sat)(sat,sun)(sun,mon)
Thus, the total number of cases = 7.
The number of cases in which we get Friday = 2(Thu, Fri)(Fri, Sat).
Therefore the required probability = 2/7.
(3.14)(21.98)(21.98)
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Answer:
Good luck!
Intelligent Muslim,
From Uzbekistan.
