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3 years ago

Find the sum. 172 + (–167) + (–10) + (–144)

Mathematics

2 answers:

quester [9]3 years ago

6 0

B. -149 yeaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa

marishachu [46]3 years ago

6 0

B is the answer you are looking for

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One week billy worked 36 hours at $6.70 per hour the next week he worked 40 hours at $6.85 per hour how much more did he earn th

krek1111 [17]

Week one:

36 * 6.70 = $241.20

Week two:

40 * 6.85 = $274

Subtract:

274 - 241.20 = $32.80

Therefore, he made $32.80 more the second week then he did the first week.

Best of Luck!

6 0

4 years ago

Which inequality matches the given situation if w represents weight in pounds:Baby tigers can be no larger than 4 pounds.

ozzi

Given:

w be the weight in pounds of a baby tigers.

To find:

The inequality if baby tigers can be no larger than 4 pounds.

Solution:

Baby tigers can be no larger than 4 pounds. It mean weight of baby tigers cannot be greater than 4. In other words, the weight of the baby tigers must be less than or equal to 4.

Let w represents weight in pounds and the weight of the baby tigers must be less than or equal to 4. So,

$w\leq 4$

Therefore, the required inequality is $w\leq 4$ .

4 0

3 years ago

Which graph represents a function

Oduvanchick [21]

Answer:

Step-by-step explanation:

Linear as said in it's name is a function that creates (visualy) a straight line.

FROM all the graphs A shows a straight line therefore, the answer.

8 0

4 years ago

How do you simplify this using the distributive property

DedPeter [7]

12/3w+36/4
4w+9
your welcome

4 0

3 years ago

A researcher wanted to see if giving a selective serotonin reuptake inhibitor (anti-depressant) would decrease the number of sel

Delvig [45]

Answer:

a. The mean of the sample is M=35.

The variance of the sample is s^2=39.125.

The standard deviation of the sample is s=6.255.

b. z=-1.6

c. SEM = 2.212

Step-by-step explanation:

The mean of the sample is M=35.

The variance of the sample is s^2=39.125.

The standard deviation of the sample is s=6.255.

Sample mean

$M=\dfrac{1}{8}\sum_{i=1}^{8}(27+25+32+40+43+37+35+38)\\\\\\ M=\dfrac{277}{8}=35$

Sample variance and standard deviation

$s^2=\dfrac{1}{(n-1)}\sum_{i=1}^{8}(x_i-M)^2\\\\\\s^2=\dfrac{1}{7}\cdot [(27-(35))^2+(25-(35))^2+(32-(35))^2+(40-(35))^2+(43-(35))^2+(37-(35))^2+(35-(35))^2+(38-(35))^2]\\\\\\$

$s^2=\dfrac{1}{7}\cdot [(58.141)+(92.641)+(6.891)+(28.891)+(70.141)+(5.64)+(0.14)+(11.39)]\\\\\ s^2=\dfrac{273.875}{7}=39.125\\\\\\s=\sqrt{39.125}=6.255$

b. If the population mean is 45, the z-score for M=35 would be:

$z=\dfrac{M-\mu}{\sigma}=\dfrac{35-45}{6.255}=\dfrac{-10}{6.255}=-1.6$

c. The standard error of the mean (SEM) of this group is calculated as:

$SEM=\dfrac{s}{\sqrt{n}}=\dfrac{6.255}{\sqrt{8}}=\dfrac{6.255}{2.828}=2.212$

4 0

3 years ago