Question

Joey has 24 coins in his pocket. The coins are all nickels and dimes. The total value of the coins is $1.85. How many dimes does Joey have? Which of the following systems is correct for this situation?
PLEASE HELP ME!!!!!!!!!! I JUST NEED THE ANSWER NO WORK!!!

Answer 1

Answer with Step-by-step explanation:

1 nickel = $ 0.05

Let there be n nickels

n nickels= $ 0.05n

1 dimes = $ 0.10

Let there be d dimes

d dimes= $ 0.10d

Joey has 24 coins in his pocket.

n+d=24

The total value of the coins is $1.85.

0.05n+0.10d=1.85

Multiplying by 100 on both sides, we get

5n+10d=185

Hence, system of equation are:

n+d=24

5n+10d=185

d=24-n

Putting it in 5n+10d=185

5(24-n)+10d=185

120-5n+10d=185

5d=65

d=13

Hence, Joey has 13 dimes

Answer 2

Answer:

Your system of equation:

n + d = 24

5n + 10d = 185

Step-by-step explanation:

Let:

nickels = $0.05; amount of dimes = n

dimes = $0.10; amount of dimes = d

There are 24 coins in all:

n + d = 24

Note the amount each coin is worth. The total value is $1.85

0.05n + 0.10d = 1.85

Move the decimal point to the right for each term.

0.05n = 5n

0.10d = 10d

1.85 = 185

5n + 10d = 185 is your new equation.

Your system of equation:

n + d = 24

5n + 10d = 185

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