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Shkiper50 [21]
3 years ago
9

What is the area of a triangle whose vertices are D(3, 3) , E(3, −1) , and F(−2, −5) ?

Mathematics
1 answer:
Jlenok [28]3 years ago
6 0

The points given are: D=(3,3),E=(3,-1),F=(-2-5)

Area of the triangle is given by:

A = \frac{1}{2}| ( x_1(y_2-y_3) + x_2(y_3-y_1) + x_3(y_1-y_2) )|

A = \frac{1}{2} |(3(-1+5) + 3(-5-3) -2(3+1))|

A = \frac{1}{2}|(3(4) + 3(-8) -2(4))|

A = \frac{1}{2} |( 12 -24 -8))|

A = \frac{1}{2} |( -20)|

A = |-10|

A = 10 \ units^2

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