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sasho [114]
3 years ago
8

Whats the gcf of 32 and 52

Mathematics
2 answers:
Molodets [167]3 years ago
7 0
The greatest common factor of 32 and 52 is: 4

Factors of 32: 1, 2, 4, 8, 16, 32
Factors of 52: 1, 2, 4, 13, 26

The common factors between them are 1, 2, 4, but the greatest common factor between them is 4.


sasho [114]3 years ago
7 0
The Greatest Common Factor (GCF) of 32 and 52 is 4.
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laura quiere cubrir con papel china una puesta como la que se muestran el dibujo cuánto centímetros cuadrados tendrá que cubrir
TEA [102]

Answer:

El área a cubrir es de 4800 cm^2.

Step-by-step explanation:

<em>La pregunta está incompleta:</em>

<em>Laura quiere cubrir con papel de china una puerta como la que se muestra en el dibujo cuánto es centímetros cuadrados. Las medidas son 80 cm de largo y 60 cm de ancho.</em>

Tenemos que calcular el área que representa la puerta, cuyos lados son 80 cm y 60 cm.

El área A se calcula multiplicando ambos lados:

A=80\,cm\cdot60\,cm=4800\,cm^2

7 0
3 years ago
Help solve -4 + n/2 = -12
Nat2105 [25]

Answer:

n=-16

Step-by-step explanation:

Add 4 on each side:

n/2 = -12+4

n/2 = -8

Multiply 2 on each side:

n=-16

6 0
2 years ago
How is 1 half to the power of 4 =to how is 1 half to the power7
deff fn [24]
Since 1/2 is 1 whole that means it’s (1x1x1x1) and (1x1x1x1x1x1x1) meaning that they both equal to 1 meaning your question is! Yes
7 0
3 years ago
Read 2 more answers
When rolling two standard six-sided dice, what is the probability that the sum of the dice will be even or a multiple of 3? (sho
aliya0001 [1]

Answer:

2/3

Step-by-step explanation:

List all the possible sums.  If it helps, make a table:

\left[\begin{array}{ccccccc} &1&2&3&4&5&6\\1&2&3&4&5&6&7\\2&3&4&5&6&7&8\\3&4&5&6&7&8&9\\4&5&6&7&8&9&10\\5&6&7&8&9&10&11\\6&7&8&9&10&11&12\end{array}\right]

There are 36 total possible sums.  Of those, 18 are even, and 6 are odd but multiples of 3.

Therefore, the probability is:

P = (18 + 6) / 36

P = 24 / 36

P = 2 / 3

8 0
3 years ago
Please help me with 21 and 22! Thank you.
Artyom0805 [142]
#21

To find the area of rectangle, you multiple length by width, so that would be (\ \sqrt{2x}\ )(\ \sqrt{6x}\ ) = \sqrt{2x\cdot6x} = \sqrt{12x^2} = x\sqrt{4\cdot3} = \boxed{2x\sqrt3}

Since we are talking about area \ length, x need to be positive so we don't need to worry about absolute value now.

#22

The area of triangle is \dfrac12bh, so that would be
\dfrac12\sqrt{18y}\cdot\sqrt{2y^4}\\\ \\=\dfrac{y^2}2\sqrt{18y}\cdot\sqrt{2}\\\ \\=\dfrac{y^2}2\sqrt{18y\cdot2}\\\ \\=\dfrac{y^2}2\sqrt{36y}\\\ \\=\dfrac{y^2}2\sqrt{4\cdot9\cdot y}\\\ \\=\boxed{3y^2\sqrt y}\text{ or }\boxed{3\sqrt{y^5}}

Hope this helps.
7 0
3 years ago
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