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3 years ago

What is an example of a memo

Computers and Technology

1 answer:

netineya [11]3 years ago

4 0

Answer:

a memo is just a importent piece text for business like if you wanted to fire someone it would be

dear, insert name here.

I belive that insert name here was trying to cheat the company for money. I was walking past his/her work space seeing that he was trying to cheat the place for money I would recomend that you should fire this person before this person makes you lose more money.

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In order to be accredited by the Better Business Bureau, a business is required to publish a privacy notice on its website that

Svetradugi [14.3K]

Answer:

Explanation:Option D (Access)

7 0

3 years ago

True or false? any webb app can be accessed and run on any computing

Mademuasel [1]

Answer:

B. False

Explanation:

A web application is a computer program that works over the internet. So, in order to access and run it you need a web browser and this will also require to have an internet access. If you don't have one of these you will not be able to run the app.

6 0

3 years ago

1. How many bits would you need to address a 2M × 32 memory if:

Dominik [7]

Answer:

a) 23 b) 21
a) 43 b) 42
a) 0 b) 0

Explanation:

<u>1) How many bits is needed to address a 2M * 32 memory </u>

2M = 2^1*2^20, while item =32 bit long word

hence ; L = 2^21 ; w = 32

a) when the memory is byte addressable

w = 8; L = ( 2M * 32 ) / 8 = 2M * 4

hence number of bits = log2(2M * 4)= log2 ( 2 * 2^20 * 2^2 ) = 23 bits

b) when the memory is word addressable

W = 32 ; L = ( 2M * 32 )/ 32 = 2M

hence the number of bits = log2 ( 2M ) = Log2 (2 * 2^20 ) = 21 bits

<u>2) How many bits are required to address a 4M × 16 main memory</u>

4M = 4^1*4^20 while item = 16 bit long word

hence L ( length ) = 4^21 ; w = 16

a) when the memory is byte addressable

w = 8 ; L = ( 4M * 16 ) / 8 = 4M * 2

hence number of bits = log 2 ( 4M * 2 ) = log 2 ( 4^1*4^20*2^1 ) ≈ 43 bits

b) when the memory is word addressable

w = 16 ; L = ( 4M * 16 ) / 16 = 4M

hence number of bits = log 2 ( 4M ) = log2 ( 4^1*4^20 ) ≈ 42 bits

<u>3) How many bits are required to address a 1M * 8 main memory </u>

1M = 1^1 * 1^20 , item = 8

L = 1^21 ; w = 8

a) when the memory is byte addressable

w = 8 ; L = ( 1 M * 8 ) / 8 = 1M

hence number of bits = log 2 ( 1M ) = log2 ( 1^1 * 1^20 ) = 0 bit

b) when memory is word addressable

w = 8 ; L = ( 1 M * 8 ) / 8 = 1M

number of bits = 0

5 0

3 years ago

We initialize the parameters to all zero values and run the linear perceptron algorithm through these points in a particular ord

Usimov [2.4K]

The main aim of running the parameters in the linear perceptron algorithm is to be able to develop a machine learning algorithm for binary classification tasks.

<h3>What is a linear perceptron algorithm?</h3>

This refers to the linear classification algorithm that is used in machine learning.

This is done in order to learn a decision boundary that divides different classes using a hyperplane.

Hence, we can see that your question is incomplete because the parameters are not included, hence a general overview was given to give you a better understanding of the concept.

Read more about machine learning here:

brainly.com/question/25523571

#SPJ1

7 0

2 years ago

Matlab In this assignment you will write a function that will calculate parallel resistance for up to 10 parallel resistors. Cal

Ket [755]

Answer:

The complete Matlab code along with step by step explanation is provided below.

Matlab Code:

function Req=ParallelR(Number)

Number=input('Please enter the number of resistors: ');

if Number>10 | Number<=0

disp('Invalid input')

return

end

R=0;

for i=1:Number

r=input('Please enter the value of resistor: ');

R=R+1/r;

end

Req=1/R;

end

Explanation:

Parallel resistance is given by

$\frac{1}{Req} = \frac{1}{R_{1}} + \frac{1}{R_{2}} + \frac{1}{R_{3}}...+\frac{1}{R_{N}}$

First we get the input from the user for how many parallel resistors he want to calculate the resistance.

Then we check whether the user has entered correct number of resistors or not that is from 1 to 10 inclusive.

Then we run a for loop to get the resistance values of individual resistors.

Then we calculated the parallel resistance and keep on adding the resistance for N number of resistors.

Output:

Test 1:

Please enter the number of resistors: 3

Please enter the value of resistor: 10

Please enter the value of resistor: 20

Please enter the value of resistor: 30

ans = 60/11

Test 2:

Please enter the number of resistors: 11

Invalid input

Test 3:

Please enter the number of resistors: 0

Invalid input

8 0

3 years ago