Answer:
a. The surface area is
b. The radius is 8 cm
Step-by-step explanation:
The surface area of a beachball is modeled by the function
Where x is the radius of the beachball.
It's given that a beachball of radius 12 cm has a surface area of
This information will allow us to find the value of a by substituting in the model:
Dividing by 144:
a = 1809.56/144
a = 12.57
The model is now:
Now we can solve parts a and b:
a . Find the surface area of a beachball of radius x=15 cm
The surface area is
b. Find the radius of a beachball with a surface area of
We need to solve:
Dividing by 12.57:
Thus:
x=8 cm
The radius is 8 cm
Answer:
S1=9.905 cubic units
Step-by-step explanation:
As the two solids are congruent it can be said that they have the same angles and the same lengths then their volume is equal and therefore S1= S2 then S1∪S2= S1+S2- S1∩S2 = S1+S1- S1∩S2 =2S1- S1∩S2 =25.
Now, S1∩ S2= Prism volume= (Area of triangle (A)*Height(h)), the area of the equilateral triangle that is the base of the prism is given by A=√3/4*(length Lateral) ^2= A=√3/4*(2^2 )=√3 square units .
Then S1∩ S2=A*h =√3*3=5. 19 cubic units .
Finally you have
2S1- S1∩S2 =25
2S1-5. 19=25 clearing s1 you have
S1=(25-5. 19)/2 = 9. 905 cubic units
Answer:
The smaller angle is 12 and the larger angle is 168
Step-by-step explanation:
Let call the measure of the random angle a. There is a angle that is 14 times of that and supplementary to that the random angle. So that is represented by
Supplementary Angles add up to 180 degrees so let set up an equation
which equal after you combine like with like
Divide 15 by both sides and a=12 and the so smaller angle is 12 and the larger angle is 168
The answer for " J " would be 228
There were an on-time departure for all 3 flights in 5 of the simulations.