3 years ago

I need help ASAP please!!

Mathematics

1 answer:

vagabundo [1.1K]3 years ago

4 0

Answer:

x = 13 , y = 29

Step-by-step explanation:

If you have any questions about the way I solved it, don't hesitate to ask!

You might be interested in

Mr Riley baked 1692 cookies he sold them in boxes 36 in each for 8 dollars

uranmaximum [27]

Answer:

He made $372

Step-by-step explanation:

1692/ 36=47

47*8=372

7 0

3 years ago

Maggie is standing in her front yard and measures the length of the shadow she casts, as well as the shadow, cast by her house.

zimovet [89]

Answer:

the answer is 57

Step-by-step explanation:

because you round to the nearest foot which it means that the answer good luck hope this helps

3 0

2 years ago

Solve the system by the method of your choice. Identify systems with no solution and systems with infinitely many solutions, usi

Ann [662]

The answer is B. because if u add 11to -8, it becomes 3 andthe other side will already be 3. so 3=3.

8 0

3 years ago

Help math question derivative!

atroni [7]

Let $f(x)=\sec^{-1}x$ . Then $\sec f(x)=x$ , and differentiating both sides with respect to $x$ gives

$(\sec f(x))'=\sec f(x)\tan f(x)\,f'(x)=1$
$f'(x)=\dfrac1{\sec f(x)\tan f(x)}$

Now, when $x=\sqrt2$ , you get

$(\sec^{-1})'(\sqrt2)=f'(\sqrt2)=\dfrac1{\sec\left(\sec^{-1}\sqrt2\right)\tan\left(\sec^{-1}\sqrt2\right)}$

You have $\sec^{-1}\sqrt2=\dfrac\pi4$ , so $\sec\left(\sec^{-1}\sqrt2\right)=\sqrt2$ and $\tan\left(\sec^{-1}\sqrt2\right)=1$ . So $(\sec^{-1})'(\sqrt2)=\dfrac1{\sqrt2\times1}=\dfrac1{\sqrt2}$

5 0

3 years ago

What is the equation of the axis of symmetry for the parabola y equals negative start fraction one over two end fraction left pa

Pachacha [2.7K]

For the equation,
y = 1/2(x+3)^2 -5
The vertice is (-3,-5). Therefore the axis of symmetry is X = -3.

7 0

3 years ago

Read 2 more answers