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Tcecarenko [31]
3 years ago
15

The circumference of each of the smaller circles is 12 mm. Find the area of the shaded region.​

Mathematics
1 answer:
podryga [215]3 years ago
8 0

Answer:

11.45mm^2

Step-by-step explanation:

Given data

Circumference= 12mm

The expression for the circumference is

C= 2πr

12= 2*3.14*r

12= 6.28r

r= 12/6.28

r= 1.91mm

Hence the area of each small circle is

A= πr^2

A= 3.14*1.91^2

A= 3.14*3.6481

A=11.45mm^2

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For the following exercises, find the average rate of change of the functions from x = 1 to x =2.
VMariaS [17]

Answer:

For the function $f(x)=4 x-3$ the average rate change from x is equal 1 to x is equal 2 is 4 .

Step-by-step explanation:

A function is given f(x)=4x-3.

It is required to find the average rate change of the function from x is 1 to x is 2 . simplify.

Step 1 of 2

A function f(x)=4 x-3 is given.

Determine the function $f\left(x_{1}\right)$ by putting the value of x=1 in the given function.

$$\begin{aligned}&f(1)=4(1)-3 \\&f(1)=1\end{aligned}$$$$f(1)=1$$

Determine the function $f\left(x_{1}\right)$ by putting the value of x is 2 in the given function.

$$\begin{aligned}&f(2)=4(2)-3 \\&f(2)=5\end{aligned}$$

Step 2 of 2

According to the formula of average rate change of the equation $\frac{\Delta y}{\Delta x}=\frac{f\left(x_{2}\right)-f\left(x_{2}\right)}{x_{2}-x_{1}}$

Substitute the value of $f\left(x_{1}\right)$ with, $f\left(x_{1}\right)$ with $3, x_{2}$ with 2 and $x_{1}$ with 1 .

$$\begin{aligned}&\frac{\Delta y}{\Delta x}=\frac{5-1}{1} \\&\frac{\Delta y}{\Delta x}=4\end{aligned}$$

3 0
2 years ago
If​ A, B, and C are the measures of the angles of any triangle and if​ a, b, and c are the lengths of the sides opposite the cor
MrRa [10]

Answer:

C. (1/2)acsinA

Step-by-step explanation:

Given is that, A, B, and C are the measures of the angles of a triangle and a, b, and c are the lengths of the sides opposite the corresponding​ angles.

So, the expression that does not represent the area of the​ triangle is :

C. (1/2)acsinA

7 0
3 years ago
if the perimeter of the rectangle was known to be 90 in what would the value of x be in order for this to be true​
Fofino [41]

Answer:

x = 30 in

Step-by-step explanation:

length of rectangle is (2/3)x + 10; width is (1/3)x + 5;

perimeter is 90 in; find x:

P = 90 in = 2(2/3)x + 2(10) + 2(1/3)x + 2(5), or

      90 in = (6/3)x + 30 in

Solving for x, we get (2)x = 60 in, or x = 30 in

8 0
3 years ago
I need to find the mean of this it's really hard for me
timama [110]
Mean is just another word for average. To find the average of something you must add up all values and divide by the number of values in the set.

4 0
3 years ago
Find the similarity ratio and the ratio of perimeters for two regular octagons with areas of 18in2 and 50in2
sweet-ann [11.9K]

Answer:

3. 3 : 5; 3: 5

Step-by-step explanation:

First, let's find the leght of the sides of each octagon.

A= 18in^{2}

The area of an octagon is defined by

A=2(1+\sqrt{2})l^{2}

Replacing the area

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Therefore, the side of the first octagon is 1.6 inches long.

Its perimeter is: P=8(2.3in)=18.4in

A=50 in^{2}

50=2(1+\sqrt{2})l^{2}\\\frac{50}{2(1+\sqrt{2})} =l^{2}\\l=\sqrt{\frac{50}{3.4} } \approx 3.8 \ in

Therefore, the side of the second octagon is 3.8 inches long.

Its perimeter is P=8(3.8in)=30.4in.

Now, let's divide to find each ratio:

\frac{3.8}{2.3} \approx 1.65 (the ratio between sides).

\frac{30.4}{18.4} \approx 1.65 (the ratio between perimeters).

Therefore, the closest ratio is 3. 3 : 5; 3: 5

8 0
3 years ago
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