Answer:
In parallelogram ABCD
FD is perpendicular to BC
BE is perpendicular to CD
Consider triangle BEC and triangle DFC
FC = EC (Given)
Angle BEC = Angle DFC (=90°)
Angle BCE = Angle DCF (common)
Therefore triangle BEC is congruent to triangle DFC (AAS congruency)
DF = BE (CPCT)
Since the altitudes are equal their bases will also be equal
Therefore BC = DC
Therefore BC = DC = AD = AB
Therefore ABCD is a rhombus
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Answer:
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d
Step-by-step explanation:
Answer:
The answer is below
Step-by-step explanation:
∠EFG and ∠GFH are a linear pair, m∠EFG = 3n+ 21, and m∠GFH = 2n + 34. What are m∠EFG and m∠GFH?
Solution:
Two angles are said to form a linear pair if they share a base. Linear pair angles are adjacent angles formed along a line as a result of the intersection of two lines. Linear pairs are always supplementary (that is they add up to 180°).
m∠EFG = 3n + 21, m∠GFH = 2n + 34. Both angles form linear pairs, hence:
m∠EFG + m∠GFH = 180°
3n + 21 + (2n + 34) = 180
3n + 2n + 21 + 34 = 180
5n + 55 = 180
5n = 125
n = 25
Therefore, m∠EFG = 3(25) + 21 = 96°, m∠GFH = 2(25) + 34 = 84°
Answer:
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Step-by-step explanation:
A quartile is a type of quantile. The first quartile (Q1) is defined as the middle number between the smallest number and themedian of the data set. The second quartile (Q2) is themedian of the data. The third quartile (Q3) is the middle valuebetween the median and the highest value of the data set.
