Question

The table below shows all of the possible outcomes for rolling two six-sided number cubes. A table with 36 possible outcomes. There are 9 desired outcomes. What is the probability of rolling an even number first and an odd number second?

Answer 1

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Answer:

The of getting an even number in first and an odd number second is $\frac{1}{4}\ or\ 0.25$.

Step-by-step explanation:

Given,

Total number of outcomes = 36

We have to find the probability of rolling an even number first and an odd number second.

Solution,

Firstly we will find out the possible outcomes;

$(2,1),\ (2,3),\ (2,5),\ (4,1),\ (4,3),\ (4,5),\ (6,1),\ (6,3),\ (6,5),$

So the total number of outcomes = 9

Now according to the formula of probability, which is;

$P(E)=\frac{\textrm{total number of possible outcomes}}{\textrm{total number of outcomes}}$

Now on putting the values, we get;

P(of getting an even number in first and an odd number second)=$\frac{9}{36}=\frac{1}{4}=0.25$

Hence The of getting an even number in first and an odd number second is $\frac{1}{4}\ or\ 0.25$.

Answer 2

Answer:

1/4

Step-by-step explanation: