Question

what is the equation of a line passing through the point (6,1) and parallel to the line whose equation 3x=2y+4

Answer 1

Answer:

The equation of the line would be y = -2/3x + 5

Step-by-step explanation:

In order to solve this, start by finding the slope of the original line. You can do this by solving for y.

3x = 2y + 4

-2y = -3x + 4

y = 3/2x - 2

Now that we have a slope of 3/2, we know that the perpendicular slope is -2/3 (since perpendicular lines have opposite and reciprocal slopes). We can use this and the new point in point-slope form to find the equation.

y - y1 = m(x - x1)

y - 1 = -2/3(x - 6)

y - 1 = -2/3x + 4

y = -2/3x + 5