Answer:
The flaw is at x=0 where the function is not defined
Step-by-step explanation:
For any function we have
The integral can be evaluated only if the function f(x) is defined in the interval [a,b] in which this integral is evaluated
In our our case function f(x) is not defined at x=0 in the interval [-1,+1] thus this results in the flaw that we have obtained in the reasoning