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3 years ago

What is the value of m? 2/3m + 3 - 5/6m = -15

2 answers:

7 0

2 over 3 (m) + 3 - 5 over 6 (m) - [-15] ➡ 0
5 over 6 (simplify )
2 over 3 (m) + 3 - 5 over 6 (m) - [-15] ➡0
2 over 3 (simplfiy)
[2 over 3 (m) + 3 - 5m over 6] - [-15] ➡ 0
2m + 9 over 3
2m + 9 over 3 - 5m over 6 - -15➡0
18 - m over 6
18 - m over 6 - [-15] ➡ 0
108 - m over 6
108 - m over 6 (6) (0)
So, the value of "m" would have to be "108"
m= 108

riadik2000 [5.3K]3 years ago

4 0

This is why you have a calculator m=3

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Using transformation (x-2 y+3) find the new coordinates of (7 -5) brainly

trasher [3.6K]

Answer:

(5, -2)

Step-by-step explanation:

In the coordinates (7, -5), 7 is the x-coordinate and -5 is the y-coordinate.

The transformation, (x-2 y+3), states that the x-coordinate, 7, must be subtracted by 2.

When subtracted by two, (7 - 2), the difference is 5.

The transformation, (x-2 y+3), states that the y-coordinate must be increased by 3.

When added by 3, (-5 + 3), the sum is -2.

Therefore, the new coordinates are (5, -2).

3 0

2 years ago

Brainliest Answer!!!

AleksandrR [38]

Its fairly straightforward. Since the bottom equation only has one unknown,x, because y=1.3, you can plug y in and solve for x. Once you find the value of x, you then have the value for two variables, x and y, and again have one unknown coefficient a. To solve for the coefficient you just plug in your y value (1.3) and your x value (which can be rounded to 0.42). Using a little bit of algebra, you can then solve for a which should be a=2.108. I am not sure if your teacher wants you to solve it this way but you could also use the elimination method or substitution method that you would of learned when discussing system of equations. But no matter which way you do it, the math follows the rules. Hope this helps. I’d suggest you solve it yourself to double check my work.

To verify my credibility,
I am a Mechanical Engineering major w/ minor in mathematics

7 0

3 years ago

How do you put 943,261,586 with base ten numbers

Citrus2011 [14]

Answer:

(9 $\times$ $10^{8}$ ) + (4 $\times$ $10^{7}$ ) + (3 $\times$ $10^{6}$ ) + (2 $\times$ $10^{5}$ ) + (6 $\times$ $10^{4}$ ) + ( $10^{3}$ ) + (5 $\times$ $10^{2}$ ) + (8 $\times$ 10) + (6 $\times$ $10^{0}$ )

Step-by-step explanation:

How do you put 943,261,586 with base ten numbers

943,261,586 =

900,000,000 + 40,000,000 + 3,000,000 + 200,000 + 60,000 + 1,000 + 500 + 80 +6 =

8 0

3 years ago

I'm having trouble with #2. I've got it down to the part where it would be the integral of 5cos^3(pheta)/sin(pheta). I'm not sur

Butoxors [25]

$\displaystyle\int\frac{\sqrt{25-x^2}}x\,\mathrm dx$

Setting $x=5\sin\theta$ , you have $\mathrm dx=5\cos\theta\,\mathrm d\theta$ . Then the integral becomes

$\displaystyle\int\frac{\sqrt{25-(5\sin\theta)^2}}{5\sin\theta}5\cos\theta\,\mathrm d\theta$
$\displaystyle\int\sqrt{25-25\sin^2\theta}\dfrac{\cos\theta}{\sin\theta}\,\mathrm d\theta$
$\displaystyle5\int\sqrt{1-\sin^2\theta}\dfrac{\cos\theta}{\sin\theta}\,\mathrm d\theta$
$\displaystyle5\int\sqrt{\cos^2\theta}\dfrac{\cos\theta}{\sin\theta}\,\mathrm d\theta$

Now, $\sqrt{x^2}=|x|$ in general. But since we want our substitution $x=5\sin\theta$ to be invertible, we are tacitly assuming that we're working over a restricted domain. In particular, this means $\theta=\sin^{-1}\dfrac x5$ , which implies that $\left|\dfrac x5\right|\le1$ , or equivalently that $|\theta|\le\dfrac\pi2$ . Over this domain, $\cos\theta\ge0$ , so $\sqrt{\cos^2\theta}=|\cos\theta|=\cos\theta$ .

Long story short, this allows us to go from

$\displaystyle5\int\sqrt{\cos^2\theta}\dfrac{\cos\theta}{\sin\theta}\,\mathrm d\theta$

to

$\displaystyle5\int\cos\theta\dfrac{\cos\theta}{\sin\theta}\,\mathrm d\theta$
$\displaystyle5\int\dfrac{\cos^2\theta}{\sin\theta}\,\mathrm d\theta$

Computing the remaining integral isn't difficult. Expand the numerator with the Pythagorean identity to get

$\dfrac{\cos^2\theta}{\sin\theta}=\dfrac{1-\sin^2\theta}{\sin\theta}=\csc\theta-\sin\theta$

Then integrate term-by-term to get

$\displaystyle5\left(\int\csc\theta\,\mathrm d\theta-\int\sin\theta\,\mathrm d\theta\right)$
$=-5\ln|\csc\theta+\cot\theta|+\cos\theta+C$

Now undo the substitution to get the antiderivative back in terms of $x$ .

$=-5\ln\left|\csc\left(\sin^{-1}\dfrac x5\right)+\cot\left(\sin^{-1}\dfrac x5\right)\right|+\cos\left(\sin^{-1}\dfrac x5\right)+C$

and using basic trigonometric properties (e.g. Pythagorean theorem) this reduces to

$=-5\ln\left|\dfrac{5+\sqrt{25-x^2}}x\right|+\sqrt{25-x^2}+C$

4 0

3 years ago

Read 2 more answers

An airplane descends 1.5 miles to an elevation of 5.25 miles. Write and solve an equation to find the elevation of the plane bef

DerKrebs [107]

2.25 is the elevation of the plane before its decent

7 0

3 years ago