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Gre4nikov [31]
3 years ago
8

What is the value of m? 2/3m + 3 - 5/6m = -15

Mathematics
2 answers:
polet [3.4K]3 years ago
7 0
2 over 3 (m) + 3 - 5 over 6 (m) - [-15] ➡ 0
5 over 6 (simplify )
2 over 3 (m) + 3 - 5 over 6 (m) - [-15] ➡0
2 over 3 (simplfiy)
[2 over 3 (m) + 3 - 5m over 6] - [-15] ➡ 0
2m + 9 over 3
2m + 9 over 3 - 5m over 6 - -15➡0
18 - m over 6
18 - m over 6 - [-15] ➡ 0
108 - m over 6
108 - m over 6 (6) (0)
So, the value of "m" would have to be "108"
m= 108
riadik2000 [5.3K]3 years ago
4 0
This is why you have a calculator m=3
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If 3500 miles are traveled at a rate of 175 miles per hour, what is the time in hours? (hint: Distance = Rate * Time)
laiz [17]
3500 miles divided by 175 Miles Per Hour. 3500/175=20 Hours.
4 0
3 years ago
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Ede4ka [16]
Given the expression
-2 + 6.45z - 6 + (-3.25z)

First, classify like terms, constant with constant, coefficient-variable with coefficient-variable
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= 6.45z + (-3.25z) - 2 - 6
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8 0
3 years ago
A trucking firm suspects that the mean life of a certain tire. it uses is less than 33,000 miles. To check the claim, the firm r
Mice21 [21]

Answer:

We accept the alternate hypothesis. We conclude that the mean lifetime of tires is  is less than 33,000 miles.

Step-by-step explanation:

We are given the following in the question:  

Population mean, μ = 33,000 miles

Sample mean, \bar{x} =  32, 450 miles

Sample size, n = 18

Alpha, α = 0.05

Sample standard deviation, s = 1200 miles

a) First, we design the null and the alternate hypothesis

H_{0}: \mu = 33000\text{ miles}\\H_A: \mu < 33000\text{ miles}

b) Level of significance:

\alpha = 0.05

c) We use One-tailed t test to perform this hypothesis.

d) Formula:

t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{s}{\sqrt{n}} } Putting all the values, we have

t_{stat} = \displaystyle\frac{32450 - 33000}{\frac{1200}{\sqrt{18}} } = -1.9445

Now, t_{critical} \text{ at 0.05 level of significance, 17 degree of freedom } = -1.7396

Rejection area:

t < -1.7396

Since,                  

t_{stat} < t_{critical}

e) We fail to accept the null hypothesis and reject it as the calculated value of t lies in the rejection area.

f) We accept the alternate hypothesis. We conclude that the mean lifetime of tires is  is less than 33,000 miles.

3 0
3 years ago
Can you please solve the following equation?
AlladinOne [14]

Answer:

x=3.903

Step-by-step explanation:

2^{x-3}.5^{x-1}=200\\2^x.2^{-3}.5^x.5^{-1}=200\\\frac{2^x}{2^3}.\frac{5^x}{5^1}=200\\\frac{2^x.5^x}{2^3.5}=200\\\frac{(2.5)^x}{8.5}=200\\10^x=200 \times 40\\10^x=8000\\log 10^x=log8000\\x=\frac {log8000}{log10}=log8000=log 8\times log1000=log 8+log 1000=log2^3+log10^3=3log2+3log10=3log2+3 \approx0.903+3 \approx3.903

7 0
3 years ago
What is 20/16=d/12? what equals d?
ozzi

Answer:

  d = 15

Step-by-step explanation:

Divide the numbers

\frac{20}{16} =\frac{d}{12}

\frac{5}{4} =\frac{d}{12}

Multiply all terms by the same value to eliminate fraction denominators

12*\frac{5}{4} =12*\frac{d}{12}

Cancel multiplied terms that are in the denominator

12*\frac{5}{4} =d

Multiply the numbers

15=d

Move the variable to the left

d=15

Hence, d= 15.

[RevyBreeze]

8 0
2 years ago
Read 2 more answers
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