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3 years ago

11

Lilian exercises times a week. She runs miles each morning and bikes in the evening. If she exercises a total of miles for the w

eek, how many miles does she bike each evening? WRITE AN EXPRESSION AND SHOW YOUR ANSWER

2 answers:

Eduardwww [97]3 years ago

7 0

Dude you didn’t put any of the info in the question

professor190 [17]3 years ago

6 0

There wasn't anything there to answer

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A sales person is paid a weekly salary of $760, plus a commission of 7.5% of all her sales for the week. Express her weekly inco

Elis [28]

Answer:

1. We can see that salesperson's weekly income is the sum of her constant weekly salary ($760) and a commission which is variable and depends on her weekly sales.

So, if we say that y is her weekly income and x is her weekly sales, we can write this as:

y = 760 + 0.075x

Note that we had to change percentage to decimal number dividing it by 100.

2 Since for each value of x there is only one corresponding value of y, we can say that this is a function. For any value of x we input there is only one solution we get - that is the main feature of function and a way to tell if something is really a function.

Since this is a function, it can also be written as:

f(x) = 760 + 0.075x

3. Domain of a function is, basically, set of all values of x for which the function can work. That practically means that, since x is weekly sale, it can not be negative (one cannot make -$500 sale, for example). However, it is possible that she doesn't make a sale one week, making it possible for x to be 0. Also, the value of her sales doesn't have to be integer (it is quite possible that she makes $673.50 sale).

All this means that appropriate domain for this function are positive real numbers including 0.

6 0

4 years ago

#54 Simplify and write the answers using positive exponents only.

kramer

Gg easy

remember
(x^m)/(x^n)=x^(m-n)
and
(x^m)^n=x^(mn)
and
(xyz)^m=(x^m)(y^m)(z^m)
and
(m/n)^a=(m^a)/(n^a)
and
x^-n=1/(x^n)

so
$( \frac{6mn^{-2}}{3m^{-1}n^2} )^{-3}$ =
$( \frac{6}{3} )^{-3}( \frac{m}{m^{-1}} )^{-3}( \frac{n^{-2}}{n^2} )^{-3}$ =
$(2^{-3})((m^2)^{-3})((n^{-4})^{-3})$ =
$( \frac{1}{2^3})(m^{-6})(n^{12})$ =
$( \frac{1}{8} )( \frac{1}{m^6})(n^{12})$ =
$\frac{n^{12}}{8m^6}$

8 0

3 years ago

Vector v has a direction of (-4,27) find the direction angle for v

mixas84 [53]

$\bf \begin{array}{lclll}
\ \textless \ &-4&,&27\ \textgreater \ \\
&\uparrow &&\uparrow \\
&a&&b
\end{array}\qquad tan(\theta)=\cfrac{b}{a}\implies \measuredangle \theta=tan^{-1}\left( \frac{b}{a} \right)
\\\\\\
\measuredangle \theta=tan^{-1}\left( \frac{27}{-4} \right)$

8 0

3 years ago

Luden [163]

Cone details:

height: h cm

radius: r cm

Sphere details:

radius: 10 cm

================

From the endpoints (EO, UO) of the circle to the center of the circle (O), the radius is will be always the same.

<u>Using Pythagoras Theorem</u>

(a)

TO² + TU² = OU²

(h-10)² + r² = 10² [insert values]

r² = 10² - (h-10)² [change sides]

r² = 100 - (h² -20h + 100) [expand]

r² = 100 - h² + 20h -100 [simplify]

r² = 20h - h² [shown]

r = √20h - h² ["r" in terms of "h"]

(b)

volume of cone = 1/3 * π * r² * h

===========================

$\longrightarrow \sf V = \dfrac{1}{3} * \pi * (\sqrt{20h - h^2})^2 \ ( h)$

$\longrightarrow \sf V = \dfrac{1}{3} * \pi * (20h - h^2) (h)$

$\longrightarrow \sf V = \dfrac{1}{3} * \pi * (20 - h) (h) ( h)$

$\longrightarrow \sf V = \dfrac{1}{3} \pi h^2(20-h)$

To find maximum/minimum, we have to find first derivative.

(c)

<u>First derivative</u>

$\Longrightarrow \sf V' =\dfrac{d}{dx} ( \dfrac{1}{3} \pi h^2(20-h) )$

<u>apply chain rule</u>

$\sf \Longrightarrow V'=\dfrac{\pi \left(40h-3h^2\right)}{3}$

<u>Equate the first derivative to zero, that is V'(x) = 0</u>

$\Longrightarrow \sf \dfrac{\pi \left(40h-3h^2\right)}{3}=0$

$\Longrightarrow \sf 40h-3h^2=0$

$\Longrightarrow \sf h(40-3h)=0$

$\Longrightarrow \sf h=0, \ 40-3h=0$

$\Longrightarrow \sf h=0,\:h=\dfrac{40}{3}$ <u />

<u>maximum volume:</u> <u>when h = 40/3</u>

$\sf \Longrightarrow max= \dfrac{1}{3} \pi (\dfrac{40}{3} )^2(20-\dfrac{40}{3} )$

$\sf \Longrightarrow maximum= 1241.123 \ cm^3$

<u>minimum volume:</u> <u>when h = 0</u>

$\sf \Longrightarrow min= \dfrac{1}{3} \pi (0)^2(20-0)$

$\sf \Longrightarrow minimum=0 \ cm^3$

6 0

2 years ago

Read 2 more answers

The price p of pizza is $7.25 plus $0.70 for each t topping on the pizza write a function rule that represents the situation

IrinaK [193]

The answer is

p=7.25+0.70t

5 0

3 years ago