What is the first step in solving the inequality 2x + 3 2 17?

A line passes through (3,-2) and (6, 2). Write an equation for the line in point-slope form.

yKpoI14uk [10]

Answer:

(y - -2) (6 - 3) - (2 - -2) (x - 3) = 0

6y + 2 - 3y - 6 -2x +6 +2x +6 = 0

3y +8 =0

3y = -8

y = -8/3

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Select all the equations that are true when “x” is (-2).

mina [271]

Answer:

The first one, the third one, and the fourth one.

Step-by-step explanation:

i just put the ones that are correct. If you want me to write out why the incorrect ones are incorrect, let me know.

1.

-6=3x

-6= 3(-2)

-6= -6

3. -8= x+x+x+x

-8= -2+-2+-2+-2

-8= -8

4. x/2= (-1)

-2/2 =(-1)

-1= -1

6 0

3 years ago

What is x? Please help fast

Firdavs [7]

Answer:

x = 47°

Step-by-step explanation:

m∠DPB + ∠BPC = 180° (Definition of a straight line)

Plug in the corresponding numbers and variables to the corresponding places:

x + 133 = 180

Isolate the variable, x. Subtract 133 from both sides:

x + 133 (-133) = 180 (-133)

x = 180 - 133

x = 47

47° is your answer.

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3 0

2 years ago

Read 2 more answers

What is the answer to 3z > - 4.5

Stella [2.4K]

Answer:

$z$

Step-by-step explanation:

$3z > -4.5$

$z > - \frac{4.5}{3}$

$z > -1.5$

$z < 1.5$

3 0

3 years ago

Solve | x + 6| - 7 = 8

Alex

Answer:

x = 9,-21

Step-by-step explanation:

Given:

$\displaystyle \large{|x+6|-7=8}$

Transport -7 to add 8:

$\displaystyle \large{|x+6|=8+7}\\\displaystyle \large{|x+6|=15}$

Cancel absolute sign and add plus-minus to 15:

$\displaystyle \large{x+6=\pm 15}$

Transport 6 to subtract ±15:

$\displaystyle \large{x=\pm 15-6}$

Consider:

$\displaystyle \large{x= 15-6}$ or $\displaystyle \large{x = -15-6}$

$\displaystyle \large{x=9}$ or $\displaystyle \large{x=-21}$

Solution:

$\displaystyle \large{x = 9}$ or $\displaystyle \large{x=-21}$

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Second Method

Given:

$\displaystyle \large{|x+6|-7=8}$

Transport -7 to add 8:

$\displaystyle \large{|x+6|=8+7}\\\displaystyle \large{|x+6|=15}$

Absolute Function Property:

$\displaystyle \large{|x-a| = \begin{cases} x-a \ \ (x \geq a) \\ -x+a \ \ (x < a) \end{cases}}$

Consider both intervals:

When x ≥ a then:

$\displaystyle \large{|x+6|=15}\\\displaystyle \large{x+6=15}$

Transport 6 to subtract 15:

$\displaystyle \large{x=15-6}\\\displaystyle \large{x=9}$

When x < a then:

$\displaystyle \large{|x+6|=15}\\\displaystyle \large{-(x+6)=15}\\\displaystyle \large{-x-6=15}$

Transport -6 to add 15:

$\displaystyle \large{-x=15+6}\\\displaystyle \large{-x=21}$

Transport negative sign to 21:

$\displaystyle \large{x=-21}$

Solution:

$\displaystyle \large{x=9}$ or $\displaystyle \large{x=-21}$

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Let me know if you have any questions regarding this question, my answer or explanation. Hope this answer and explanation helps you and good luck with your assignment!

3 0

2 years ago