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3 years ago

Find the area. i need help ASAP please!

Mathematics

2 answers:

DENIUS [597]3 years ago

6 0

9 times 27=243

13 times 17=221

243+221=464

VLD [36.1K]3 years ago

5 0

This is a composite figure, so it will be easier to break it up into two shapes. We can split it into two rectangles, one measuring 17 by 13 km and another 9 by (40 - 13) km.

The area of the 17 by 13 rectangle is 17 * 13 = 221, while the area of the other rectangle is 9 * 27 = 243.

Add these two areas together and you get 243 + 221 = 464 km squared.

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A farmer paid $500 per month for deliveries over 10 months. For the other 2 months of the year, he paid $600 per month. Which nu

PolarNik [594]

The answer is option .. A : 500(10) + 600(2)
I Just took the assignment and that is the Correct Answer :)

7 0

2 years ago

D+7/−3=4<br> What is d?<br> Thanks!

givi [52]

Answer

$\boxed {d= \frac{19}{3}}$

Solution

Simplify both sides of the equation.

$\frac{7}{3} + \frac{-7}{3}$

We are left with d = 4+ $\frac{7}{3}$

Add

$\frac{12}{3}+\frac{7}{3} =\frac{19}{3}$

Hence, d = $\frac{19}{3}$

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3 years ago

Find the slope of the line that passes through (10,8) and (9,13)

Scilla [17]

Se usa está formula

m= pendiente

m=Y2-Y1/X2-X1

Resolución

13-8/9-10= 5/-1= -5

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3 0

3 years ago

According to a Los Angeles Times study of more than 1 million medical dispatches from to , the response time for medical aid var

-BARSIC- [3]

Answer:

A)Mean :10.65

Median =10.7

Mode : 10.7

B)Range = 3.5

Standard deviation :0.89916

C)The response time of 8.3 minutes should be considered an outlier in comparison to the other response times

Step-by-step explanation:

Data : 11.8 ,10.3, 10.7, 10.6, 11.5, 8.3, 10.5, 10.9, 10.7, 11.2

$Mean = \frac{\text{Sum of all observations}}{\text{No. of observations}}\\Mean = \frac{11.8 +10.3+ 10.7+ 10.6+ 11.5+ 8.3+ 10.5+ 10.9+ 10.7+ 11.2}{10}$

Mean = 10.65

Median: The mid value of the data

Data in ascending order

8.3

10.3

10.5

10.6

10.7

10.9

11.2

11.5

11.8

n=10(even)

$Median = \frac{(\frac{n}{2})\text{th term}+(\frac{n}{2}+1)\text{th term}}{2}\\Median = \frac{(\frac{10}{2})\text{th term}+(\frac{10}{2}+1)\text{th term}}{2}\\Median = \frac{10.7+10.7}{2}\\Median = 10.7$

Mode : the most occurring frequency

10.7 is occurring twice while others are occurring once

So, Mode is 10.7

B) Range = Maximum - Minimum=11.8-8.3=3.5

Standard deviation : $\sqrt{\frac{\sum(x-\bar{x})^2}{n}}$

Standard deviation : $\sqrt{\frac{(11.8-10.65)^2+(10.3-10.65)^2+......+(10.9-10.65)^2+(10.7-10.65)^2+(11.2-10.65)^2}{10}}$

Standard deviation :0.89916

8.3

,10.3

,10.5

,10.6

,10.7

,10.9

,11.2

,11.5

,11.8

For Q1 ( Median of lower quartile )

8.3

,10.3

,10.5

,10.6

,10.7

$Median = \frac{n+1}{2}\text{th term} =\frac{5+1}{2}=3 \text{rd term}=10.5$

For Q3( Median of Upper quartile )

10.7

,10.9

,11.2

,11.5

,11.8

$Median = \frac{n+1}{2}\text{th term} =\frac{5+1}{2}=3 \text{rd term}=11.2$

IQR = Q3-Q1=11.2-10.5=0.7

Range :(Q1-1.5IQR, Q3-1.5IQR)

Range : $(10.5-1.5 \times 0.7, 11.2-1.5 \times 0.7)$

Range :(9.45, 10.15)

8.3 does not lie in this interval

So, the response time of 8.3 minutes should be considered an outlier in comparison to the other response times

3 0

2 years ago

Part B Lawyer B charges an hourly rate and an up-front fee of $650. He

Anastasy [175]

Answer:

(5490-650) ÷ 22 = Y

Step-by-step explanation:

3 0

2 years ago