Answer:
95% confidence for µ, the average number of times a horse races
(12.493 , 18.107)
Step-by-step explanation:
<u>Explanation</u>:-
The veterinarian finds that the average number of races a horse enters is 15.3
The mean of the sample x⁻ = 15.3
Given standard deviation of the sample 'S' = 6.8
Given sample size 'n' = 25
Degrees of freedom = n-1 =25-1 =24
The tabulated value 't' = 2.064 at two tailed test 0.95 level of significance
<u> 95% confidence for µ, the average number of times a horse races</u>
<u></u>
<u></u>
<u></u>
<u></u>
(15.3 - 2.80704 ,15.3 +2.80704)
(12.493 , 18.107)
<u>Conclusion</u>:-
95% confidence for µ, the average number of times a horse races
(12.493 , 18.107)
Hi there! We are looking for the percentage of the fraction. In order to do this, first, let's divide. 41/50 is 0.82. Percents are parts of 100, so let's multiply that decimal by 100. 0.82 * 100 is 82. There. 41/50 is equivalent to 82%.
Answer:
1.20
Step-by-step explanation:
Because .2 is in the tenths place and 0 is the hundredths so you round the hundredths to the tenths and since its 0 then it stays the same.
Answer:
the answer is -30.
Step-by-step explanation:
for each x-value, you will multiply it by -5 to get your y-value. i say this because if y-15 when x=-3, if you divide the x from y (so 15/-3) you get -5 which is the number in which y varies by. so you will take 6 and multiply it by -5 which gives you -30.
For this case you can model the problem as a rectangle triangle where you have the length of the opposite leg and the adjacent leg.
Therefore, the angle sought is given by:
theta = Atan (8/15)
theta = 28.07 degrees
Answer:
The angle between its diagonal and a longer edge is:
theta = 28.07 degrees
