All categories

3 years ago

A bumper sticker has an area of five 24 ft.² which model correct present the area of the bumper sticker

1 answer:

6 0

A picture types of the models would be helpful.. but they could be found in a rectangular shape or square such as width=2 and length =12 vise versa or w=4 and length = 6 , etc etc

You might be interested in

HELPPPPPPPPP 55 POINTS Isabel graphed the following system of equations.

Arturiano [62]

Answer:

1. Substitute y = -3x +4 for y in the first equation

2. Combine like terms and isolate x

3. Substitute in x into the 2nd equation to get y

Step-by-step explanation:

1. Substitute y = -3x +4 for y in the first equation

2x- (-3x+4) = 6

2. Combine like terms

5x -4 = 6

5x -4 +4 = 6+4

5x=10 Divide by 5 to isolate x

5x/5 =10/5

x=2

3. Substitute in x into the 2nd equation to get y

y = -3x +4

y = -3(2) +4

y = -6+4

y=-2

(2,-2)

5 0

3 years ago

A public bus company official claims that the mean waiting time for bus number 14 during peak hours is less than 10 minutes. Kar

ch4aika [34]

Answer:

We conclude that the mean waiting time is less than 10 minutes.

Step-by-step explanation:

We are given that a public bus company official claims that the mean waiting time for bus number 14 during peak hours is less than 10 minutes.

Karen took bus number 14 during peak hours on 18 different occasions. Her mean waiting time was 7.8 minutes with a standard deviation of 2.5 minutes.

Let $\mu$ = mean waiting time for bus number 14.

So, Null Hypothesis, $H_0$ : $\mu \geq$ 10 minutes {means that the mean waiting time is more than or equal to 10 minutes}

Alternate Hypothesis, $H_A$ : $\mu$ < 10 minutes {means that the mean waiting time is less than 10 minutes}

The test statistics that would be used here One-sample t test statistics as we don't know about the population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean waiting time = 7.8 minutes

s = sample standard deviation = 2.5 minutes

n = sample of different occasions = 18

So, test statistics = $\frac{7.8-10}{\frac{2.5}{\sqrt{18} } }$ ~ $t_1_7$

= -3.734

The value of t test statistics is -3.734.

Now, at 0.01 significance level the t table gives critical value of -2.567 for left-tailed test.

Since our test statistic is less than the critical value of t as -3.734 < -2.567, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that the mean waiting time is less than 10 minutes.

5 0

3 years ago

A total of 937 people attended the play.

insens350 [35]

Answer:

1.75

2.25

1083.00

now we still know, that

508

−

so we can substitute it into the second formula

1.75

2.25

(

508

−

)

1083

now its just simple algebra

1.75

1143

−

2.25

1083

0.5

so:

120

Step-by-step explanation:

6 0

3 years ago

Suppose we want to choose 6 letters, without replacement, from 15 distinct letters. (A) how many ways can this be done, if the o

Olenka [21]

Answer:

Below in bold.

Step-by-step explanation:

A.This is the number of combinations of 6 from 15

= 15C6

= 15! / (15-6)! 6!

= 5,005 ways.

B. This is the number of permutaions of 6 from 15:

= 15! / (15-6)!

= 3,603,600 ways.

7 0

3 years ago

An online news source reports that the proportion of smartphone owners who use a certain operating system is 0.216. Two simulati

kaheart [24]

Answer:

The center/ mean will almost be equal, and the variability of simulation B will be higher than the variability of simulation A.

Step-by-step explanation:

Solution

Normally, a distribution sample is mostly affected by sample size.

As a rule, sampling error decreases by half by increasing the sample size four times.

In this case, B sample is 2 times higher the A sample size.

Now, the Mean sampling error is affected and is not higher for A.

But it's sample is huge for this, Thus, they are almost equal

Variability of simulation decreases with increase in number of trials. A has less variability.

With increase number of trials, variability of simulation decreases, so A has less variability.

4 0

3 years ago