All categories

2 years ago

How many even numbers are there between 1 to 540

2 answers:

6 0

To find the number of even factors, we can multiply the number of odd factors by the power of 2 (not the power of 2 + 1!!!). For 540, we have (3 + 1)(1 + 1)(2) = 16 even factors.

irina [24]2 years ago

3 0

Answer:

271

Step-by-step explanation:

The count of even numbers between 0 and n is [n/2] + 1.

540/2=270

270+1=

271

You might be interested in

HL ASA SSS AAS SAD Not congruent

maria [59]

Answer: 4

Step-by-step explanation:

i think

8 0

2 years ago

What is the slope of the line in the graph?

Bingel [31]

Answer:

The slope equals the rise divided by the run:

7 0

2 years ago

Let m=4 and n=36. What is the value of m+.9?

Anna11 [10]

Answer:
4.9

Explanation:
We are given m = 4 and n = 36 and the expression m + .9.

Replace m with the given value:
4 + .9

Add them together:
4.9

3 0

2 years ago

There are 50 campers at day camp and 10 counselors. Write the ratio of campers to counselor as a fraction . Explain how to use e

nadezda [96]

Take the common denominator and divide by 3 then youll get 58

4 0

3 years ago

The average number of mosquitoes in a stagnant pond is 80 per square meter with a standard deviation of 12. If 36 square meters

svp [43]

Answer:

a) 18.4%

Step-by-step explanation:

Assuming a normal distribution, the z-score (z) for the probability of the average of the mosquitoes count being 'X' is given by:

$z(X)=\frac{X-\mu }{\frac{\sigma}{\sqrt{n}}}$

Where 'μ' is the distribution mean, 'σ' is the standard deviation and 'n' is the number of square meters chosen.

For X = 81.8 and n=36:

$z(X)=\frac{81.8 - 80}{\frac{12}{\sqrt{36}}}\\z(X)= 0.9$

A z-score of 0.9 is equivalent to the 81.59 th percentile in a normal distribution.

Therefore, the probability (P) that the average of those counts is more than 81.8 mosquitoes per square meter is:

$P= 100\% - 81.59\%\\P=18.41\%$

8 0

2 years ago