When rounding here are the rules
If the next number to the right is 1-4, you will round down or keep the # the same.
If the next number to the right is 5-9, you will round up to the next number.
So with your # 281,421,906
a. hundred million. This is the first 2...the number to the right of it is 8, so we will round the 2 up. And the answer is 300,000,000
b. ten million. This is the 8...the number to the right of it is 1, so we will round it down and 8 will remain an 8. And the answer is 280,000,000
c. million. This is the first 1 (281)...the number to the right is 4, so we will round down and 1 will remain a 1. And the answer is 281,000,000
d. hundred thousand. This is the 4...the number to the right of it is 2, so we will round down and the 4 will remain a 4. And the answer is 281,400,000
e. thousand. This is the second 1 (281,421)...the number to the right is the 9, so we will round up and the 1 will become a 2. And the answer is 281,422,000
Now for #14, think about the rules.
1. If you round it to the nearest one, you get 7.
2. If you round it to the nearest tenth, you get 7.0.
3. If you round it o the nearest hundredth, you get 7.00
4. It is the least number that fits the clues.
Ok basically it is saying, it rounds up to 7. So what would be the number that would round UP to 7? That would be 6. I'm rounding UP because it says it is the LEAST number that fits the clues.
Answer:
The family's average rate of travel for the day was 59.0 MPH.
Step-by-step explanation:
From 10:15AM to 4:45PM, they travelled a distance of 383.5 miles and a total of 6 hours and 30 minutes.
There are 60 minutes in an hour. 30 minutes translates into 1/2 an hour or .5
So, 6.5 hours and a total distance of 383.5 miles.
Velocity (MPH) = Distance (in miles) / Time (in hours)
MPH means Miles Per Hour
Variables:
Velocity (MPH) = x
Distance (in miles) = 383.5
Time (in hours) = 6.5
Plug in the variables into the formula
x = 383.5 / 6.5
Divide
x = 59.0 MPH
<span>B. It must be the same as when he constructed the arc centered at point A.
This problem would be a lot easier if you had actually supplied the diagram with the "arcs shown". But thankfully, with a few assumptions, the solution can be determined.
Usually when constructing a perpendicular to a line through a specified point, you first use a compass centered on the point to strike a couple of arcs on the line on both sides of the point, so that you define two points that are equal distance from the desired intersection point for the perpendicular. Then you increase the radius of the compass and using that setting, construct an arc above the line passing through the area that the perpendicular will go. And you repeat that using the same compass settings on the second arc constructed. This will define a point such that you'll create two right triangles that are reflections of each other. With that in mind, let's look closely at your problem to deduce the information that's missing.
"... places his compass on point B ..."
Since he's not placing the compass on point Q, that would imply that the two points on the line have already been constructed and that point B is one of those 2 points. So let's look at the available choices and see what makes sense.
A .It must be wider than when he constructed the arc centered at point A.
Not good. Since this implies that the arc centered on point A has been constructed, then it's a safe assumption that points A and B are the two points defined by the initial pair of arcs constructed that intersect the line and are centered around point Q. If that's the case, then the arc centered around point B must match exactly the setting used for the arc centered on point A. So this is the wrong answer.
B It must be the same as when he constructed the arc centered at point A.
Perfect! Look at the description of creating a perpendicular at the top of this answer. This is the correct answer.
C. It must be equal to BQ.
Nope. If this were the case, the newly created arc would simply pass through point Q and never intersect the arc centered on point A. So it's wrong.
D.It must be equal to AB.
Sorta. The setting here would work IF that's also the setting used for the arc centered on A. But that's not guaranteed in the description above and as such, this is wrong.</span>
Answer:
I don't think many schools do Powderpuff which is where boys cheer and girls play football. You can do a live Insta and congratulate the students who made the team and mail them gift cards and/or gift baskets. You can also buy basket balls and footballs for each member and decorate it with their names and numbers. I'm also in Student Council so, if you have any other questions feel free to post them!!
