The question given is incomplete and by finding it on internet i found the complete question as follows:
Direct Mapped Cache.
Memory is byte addressable
Fill in the missing fields based upon the properties of a direct-mapped cache. Click on "Select" to access the list of possible answers Main Memory Size Cache Size Block Size Number of Tag Bits 3 1) 16 KiB 128 KiB 256 B 20 2) 32 GiB 32 KiB 1 KiB 3) 64 MiB 512 KiB 1 KiB Select] 4 KiB 4) 16 GiB 10 Select ] Select ] 5) 10 64 MiB [ Select ] 6) Select] 512 KiB 7
For convenience, the table form of the question is attached in the image below.
Answers of blanks:
1. 3 bits
2. 20 bits
3. 64 MB
4. 16 MB
5. 64 KB
6. 64 MB
Explanation:
Following is the solution for question step-by-step:
<u>Part 1:</u>
No. of Tag bits = No. of bits to represent
Tag bits = Main memory - cache size bits -------- (A)
Given:
Main memory = 128 KB = 
Cache Memory = 16 KB = 
Putting values in A:
Tag bits = 17 - 14 = 3 bits
<u>Part 2:</u>
Tag bits = Main memory - cache size bits -------- (A)
Given:
Main memory = 32 GB = 
Cache Memory = 16 KB = 
Putting values in A:
Tag bits = 35 - 15 = 20 bits
<u>Part 3:</u>
Given:
Tag bits = 7
Cache Memory = 512 KB = 
So from equation A
7 = Main Memory size - 19
Main Memory = 7 + 19
Main memory = 26
OR
Main Memory = 
<u>Part 4:</u>
Given that:
Main Memory Size = 
Tag bits = 10
Cache Memory Bits = 34 - 10 = 24
Cache Memory Size = 
<u>Part 5:</u>
Given that:
Main Memory Size = 64 MB = 
Tag bits = 10
Cache Memory Bits = 26 - 10 = 16
Cache Memory Size = 
<u>Part 6:</u>
Cache Memory = 512 KB = 
Tag Bits = 7
Main Memory Bits = 19 + 7 = 26
Main Memory size = 
i hope it will help you!
Hello This Answer Is Not Real This Is All A Simulation
Answer:
Following are the answer to this question:
Explanation:
In option 1:
The value of n is= 7, which is (base case)

when n=k for the true condition:

when n=k+1 it tests the value:

since k>6 hence the value is KH>3 hence proved.
In option 2:
when:
for n=1:(base case)

0<=0 \\ condition is true
when the above statement holds value n=1
when n=k

when n=k+1


![[\therefore KH>K \Rightarrow \log(KH>\loK)]](https://tex.z-dn.net/?f=%5B%5Ctherefore%20KH%3EK%20%5CRightarrow%20%20%5Clog%28KH%3E%5CloK%29%5D)
In option 3:
when n=1:

when n=k
![\to (A_1\cap A_2 \cap.....A_k) \cup B\\=(A_1\cup B) \cap(A_2\cup B_2)....(A_k \capB).....(a)\\\to n= k+1\\ \to (A_1\cap A_2 \cap.....A_{kH}) \cup B= (A_1\cup B)\\\\\to [(A_1\cap A_2 \cap.....A_{k}) \cup B]\cap (A_{KH}\cup B)\\\\\to [(A_1\cup B) \cap (A_2 \cup B) \cap (A_3\cup B).....(A_k\cup B)\cap (A_{k+1} \cup B)\\\\ \ \ \ \ \ \ substituting \ equation \ a \\\\](https://tex.z-dn.net/?f=%5Cto%20%28A_1%5Ccap%20A_2%20%5Ccap.....A_k%29%20%5Ccup%20B%5C%5C%3D%28A_1%5Ccup%20B%29%20%5Ccap%28A_2%5Ccup%20B_2%29....%28A_k%20%5CcapB%29.....%28a%29%5C%5C%5Cto%20n%3D%20k%2B1%5C%5C%20%5Cto%20%28A_1%5Ccap%20A_2%20%5Ccap.....A_%7BkH%7D%29%20%5Ccup%20B%3D%20%28A_1%5Ccup%20B%29%5C%5C%5C%5C%5Cto%20%20%5B%28A_1%5Ccap%20A_2%20%5Ccap.....A_%7Bk%7D%29%20%5Ccup%20B%5D%5Ccap%20%28A_%7BKH%7D%5Ccup%20B%29%5C%5C%5C%5C%5Cto%20%20%5B%28A_1%5Ccup%20B%29%20%5Ccap%20%28A_2%20%5Ccup%20B%29%20%5Ccap%20%28A_3%5Ccup%20B%29.....%28A_k%5Ccup%20B%29%5Ccap%20%28A_%7Bk%2B1%7D%20%5Ccup%20B%29%5C%5C%5C%5C%20%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20substituting%20%5C%20equation%20%5C%20a%20%5C%5C%5C%5C)
hence n=k+1 is true.
Expressions provide an easy way to perform operations on data values to produce other data values, True.
<h3>
What is an Expression? </h3>
An expression is a combination of one or more operands (Constant, Variable, Array element, Function), operators(Multiplication,Division, Subtraction etc) to be interpreted by a programming language following rules of precedence or association to produce other data values.
Three kinds of expressions includes:
- A logical or relational expression
Therefore, it is true that Expressions provide an easy way to perform operations on data values to produce other data values.
Answer:
Matlab code is:
>> 
>> 
>> 
>> 
>> 
>>
>> ![Vc=[M(2,:) M(:,3)']](https://tex.z-dn.net/?f=Vc%3D%5BM%282%2C%3A%29%20M%28%3A%2C3%29%27%5D)
Explanation:
>>
>> 

1 7 13 19 25
3 9 15 21 27
5 11 17 23 29
>> 
>>
>> 

>> 
>>
>> 

>>
>>
>> ![Vc=[M(2,:) M(:,3)']](https://tex.z-dn.net/?f=Vc%3D%5BM%282%2C%3A%29%20M%28%3A%2C3%29%27%5D)

>>
The code is tested and is correct. If you put a semi colon ' ; ' at the end of every statement then your answer will be calculated but matlab doesn't show it until you ask i.e. typing the variable (Va, Vb, Vc )and press enter.