Suppose the number is y >>>>>So y/2 +2y/3 <14
multiply both sides by 6>>>>>>>>>. 6y/2 +6x2y/3 <14x6
3y + 4y < 84
7y <84
y <84/7
y < 12
let dogs be heads. Let cats be tails. A coin has two sides, in which you are flipping two of them. Note that there can be the possible outcomes
h-h, h-t, t-h, t-t.
How this affects the possibility of two dogs & two cats. Note that there are 1/2 a chance of getting those two (with the others being one of each), which means that out of 4 chances, 2 are allowed.
2/4 = 1/2
50% is your answer
Heads represents cats and tails represents dogs. There is two coins because we are checking the probability of two pets. You have to do the experiment to get your set of data, once you get your set of data, you will be able to divide it into the probability for cats or dogs. To change the simulation to generate data for 3 pets, simply add a new coin and category for the new pet.
Hope this helps you out!
Answer:
c+15
Step-by-step explanation:
add the numbers c+15
c+15 is your answer.
Answer:
32.625 m
Step-by-step explanation:
You have the proportion ...
18 cm : ___ m = 22.4 cm : 40.6 m
This can be rearranged to ...
___ m/(18 cm) = (40.6 m)/(22.4 cm)
Multiplying by 18 cm gives ...
___ m = (40.6 m)·(18/22.4)
___ m = 32.625 m
