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elixir [45]
3 years ago
13

Please answer thank you

Mathematics
2 answers:
Kazeer [188]3 years ago
4 0

Answer:

Yes, it is the solution

Step-by-step explanation:

You are given the system of two inequalities

\left\{\begin{array}{l}y\le -3x+4\\ \\y>x^2+3x-2\end{array}\right.

To check whether point (0,4) is the solution to this system, substitute x=0 and y=4 into each inequality:

1.

4\le -3\cdot 0+4\\ \\4\le 4 \ [\text{true}]

2.

4>0^2+3\cdot 0-2\\ \\4>0+0-2\\ \\4>-2\ [\text{true}]

Since the coordinates of the point (0,4) satisfy both inequalities, the point (0,4) is the solution to the system

Nimfa-mama [501]3 years ago
3 0

Answer:

Yes, (0,4) is a solution

Step-by-step explanation:

We have to plug in 0 in x and 4 in y IN BOTH THE INEQUALITIES.

IF BOTH ARE TRUE, then the system of inequalities is TRUE.

<u>Let's check:</u>

y ≤ -3x+4

4 ≤ -3(0)+4

4 ≤ 4

Is 4 less than OR equal to 4? Yes. THis is satisfied.

<u>Now, checking 2nd one:</u>

y > x^2 + 3x - 2

4 > (0)^2 + 3(0) - 2

4 > -2

Is 4 greater than -2? Yes, it is. So this is satisfied as well.

Hence, (0,4) is a solution to the system of inequalities shown.

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