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Delicious77 [7]
3 years ago
9

FIRST PERSON TO ANSWER CORRECTLY GETS BRAINLIEST! MORE THAN ONE OPTION

Mathematics
2 answers:
schepotkina [342]3 years ago
8 0

Answer:

Left, open circle

Step-by-step explanation:

The graph will have an open circle, because it does not include 5 as part of the solution. The graph will only have a closed circle if the inequality sign is: \leq or\geq. Since the sign is <, it is an open circle.

The ray of the graph will move to the left, because the solution is everything less than 5. 4,3,2, 1... are all to the left of 5 on a number line, so that is the direction the ray will point.

dexar [7]3 years ago
4 0
The tay would move to the left because that is a less than sign . positive goes to the right and negative goes to the left . thing of the less sign like a L bc it looks like one .
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Kaya rented a limousine for prom. There was a one-time charge of $100 plus an hourly rate of the total
kherson [118]

Answer:

3 hours

Step-by-step explanation:

it is $100 for 1 hour right. Ok so forget about the hourly rates. Then you are left with $300. $300 total÷100 per hour = 3 hours.

3 0
2 years ago
Read 2 more answers
Solve for x: -1 &lt; x + 3 &lt; 5​
Rus_ich [418]

Answer:

−4<x<2

Step-by-step explanation:

−1<x+3<5

−1+−3<x+3+−3<5+−3  (Add -3 to all parts)

−4<x<2

3 0
3 years ago
Read 2 more answers
Find the domain of y= √3x+3
liubo4ka [24]

Answer:

it's hard to tell the exact question being asked...

y = \sqrt{3x}  + 3

or

y = \sqrt{3x+3}

if y = \sqrt{3x}  + 3 then Domain is [0 ,∞ )  

if  y = \sqrt{3x+3} then Domain is [-1 ,∞ )  

Step-by-step explanation:

6 0
2 years ago
Please help I don't understand 5i√-54
Arada [10]

Answer:

Simplify the radical by breaking the radicand up into a product of known factors.

Exact Form:

− 15 √ 6

Decimal Form:

− 36.74234614

Step-by-step explanation:

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8 0
3 years ago
Find zeroes and multiplicity for y=(2x +3)(x -1)^2
muminat

Answer:

zeros : -3/2 , multiplicity = 1

1 , multiplicity = 2

Step-by-step explanation:

y=(2x +3)(x -1)^2

To find zeros we set each factor =0  and solve for x

2x+3 =0

subtract 3 on both sides

2x= -3

divide by 2 on both sides

x= -3/2

The exponent of (2x+3) is 1 so multiplicity =1

Now we set (x-1)^2 =0

take square root on both sides

x-1 =0

add 1 on both sides

x=1

For (x-1)^2  the exponent is 2

So multiplicity = 2


7 0
3 years ago
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