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3 years ago

Just tell me the possible dimensions.

Mathematics

1 answer:

Darya [45]3 years ago

8 0

96÷6=16 - each side should have area of 16 (if it is a cube), so the lengths and widths of all sides of this cube will be $\sqrt{16}$ =4

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There are 26.2 miles in a marathon. There are approximately 8 kilometers in 5 miles. What is the best approximation of the numbe

torisob [31]

Answer:

42 km

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Angle 0 is in the second quadrant, and sin 0=3/5

Aneli [31]

ANSWER

The value of theta in the second quadrant is,

$143.1 \degree$

EXPLANATION

The given trigonometric equation is
$\sin( \theta) = \frac{3}{5}$

This implies that,

$\theta= arcsin(\frac{3}{5} )$

This implies that the principal solution is
$\theta = 36.9 \degree$
and it is an angle in the first quadrant.

But the solution we are looking for is an angle in the second quadrant.

This is given by
$180 - \theta = 180 - 36.9 = 143.1 \degree$

8 0

4 years ago

Given the pattern rule Tn=n2-1<br><br> what are the first 3 terms of the pattern

sergeinik [125]

Answer:

0, 3 , 8

Step-by-step explanation:

substitute n = 1, 2, 3 into the pattern rule

T₁ = 1² - 1 = 1 - 1 = 0

T₂ = 2² - 1 = 4 - 1 = 3

T₃ = 3² - 1 = 9 - 1 = 8

8 0

2 years ago

Drag each expression to the correct location in the equation. Not all expressions will be used.

miskamm [114]

Gotta add a picture to show us what you want us to do.

7 0

3 years ago

Read 2 more answers

Two rectangle are similar, the first 4 in wide and 15 in long. The second is 19 in. Wide. Find the length of the second rectangl

AleksandrR [38]

Answer:

the length of the second rectangle is 33.75 in

Step-by-step explanation:

The computation of the length of the second rectangle is as follows

Let us assume the length of the second triangle be x

Now

The equation would be

4 ÷ 15 = 9 ÷ x

Now do the cross multiplication

4x = 15 × 9

4x = 135

x = 33.75 in

Hence, the length of the second rectangle is 33.75 in

4 0

3 years ago