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irakobra [83]
3 years ago
14

Find an equation of the line described. Store the equation in slop-intercept form when possible.

Mathematics
1 answer:
Finger [1]3 years ago
6 0

Answer:

Y = -5

Step-by-step explanation:

The line needs to be parallel to the y-axis, which means it forms a 90° angle with the y-axis. This means the line we are looking for is a straight horizontal line. The line must pass through the point (-7, -5), but we can disregard the x value since we figured out that the line is perfecly horizontal, so it has no x value. The answer we are left with is y = -5, which is a horizontal line across -5 on the y axis.

Hopefully you can understand my explanation :)

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Simplify.
pantera1 [17]
-12 + 9 - (-3) - 11

Remember PEMDAS: This is the order of operation.
P-Paragrahp
E-Exponent
M-Multiply
D-Divide
A-Add
S-Subtract

1st step: PEM
-(-3) is actually -1 * -3 = + 3

-12 + 9 + 3 - 11

2nd step: D is not possible, so we do A.
9 + 3 = 12

3rd Step: Subtract
12 - 12 - 11 = 0 - 11 = -11 CHOICE B. 

7 0
4 years ago
1. Howard's CD House sells new CDs for $15 each and used CDs for $6 each. Bre'anna bought 51 CDs and spent a
Yanka [14]

The numbers of new CDs is 30 and the old CDs is 21.

To solve this problem, we have to write a system of equations in which we would know the numbers of each types of CD she bought.

<h3>System of Equations</h3>

This is used to solve a series or complex of word problems in which we can represent in a mathematical statements;

  • Let n represents numbers of new CDs
  • Let u represents numbers of old CDs

The equations can be represented as

n + u = 51 ...equation(i)\\15n + 6u = 576 ... equation(ii)

Let's take equation (i)

Making n the subject of formula

n + u = 51\\n = 51 - u...equation(iii)

we can put equation (iii) into equation (ii)

15n + 6u =576\\n = 51 - u\\15(51 - u) + 6u = 576\\765-15u + 6u = 576\\collect like terms\\765-576=15u - 6u\\189=9u\\9u/9 = 189/9\\u = 21

Let's put the value of u into equation (i)

n + u = 51\\u = 21\\n + 21 = 51\\n = 51 - 21\\n = 30

From the calculations above, the numbers of new CDs is 30 and the old CDs is 21.

Learn more on system of equations here;

brainly.com/question/13729904

4 0
3 years ago
A survey collected data on annual credit card charges in seven different categories of expenditures: transportation, groceries,
Andru [333]

Answer:

A. Null and alternative hypothesis:

H_0: \mu_d=0\\\\H_a:\mu_d\neq 0

B. Yes. At a significance level of 0.05, there is enough evidence to support the claim that there is signficant difference between the population mean credit card charges for groceries and the population mean credit card charges for dining out.

P-value = 0.00002

C. As the difference is calculated as (population 1 − population 2), being population 1: groceries and population 2: dinning out, and knowing there is evidence that the true mean difference is positive, we can say that the groceries annual credit card charge is higher than dinning out annual credit card charge.

The point estimate is the sample mean difference d=$840.

The 95% confidence interval for the mean difference between the population means is (490, 1190).

Step-by-step explanation:

This is a hypothesis test for the population mean.

The claim is that there is signficant difference between the population mean credit card charges for groceries and the population mean credit card charges for dining out.

Then, the null and alternative hypothesis are:

H_0: \mu_d=0\\\\H_a:\mu_d\neq 0

The significance level is 0.05.

The sample has a size n=42.

The sample mean is M=840.

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=1123.

The estimated standard error of the mean is computed using the formula:

s_M=\dfrac{s}{\sqrt{n}}=\dfrac{1123}{\sqrt{42}}=173.2827

Then, we can calculate the t-statistic as:

t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{840-0}{173.2827}=\dfrac{840}{173.2827}=4.848

The degrees of freedom for this sample size are:

df=n-1=42-1=41

This test is a two-tailed test, with 41 degrees of freedom and t=4.848, so the P-value for this test is calculated as (using a t-table):

\text{P-value}=2\cdot P(t>4.848)=0.00002

As the P-value (0.00002) is smaller than the significance level (0.05), the effect is significant.

The null hypothesis is rejected.

At a significance level of 0.05, there is enough evidence to support the claim that there is signficant difference between the population mean credit card charges for groceries and the population mean credit card charges for dining out.

We have to calculate a 95% confidence interval for the mean difference.

The t-value for a 95% confidence interval and 41 degrees of freedom is t=2.02.

The margin of error (MOE) can be calculated as:

MOE=t\cdot s_M=2.02 \cdot 173.283=350

Then, the lower and upper bounds of the confidence interval are:

LL=M-t \cdot s_M = 840-350=490\\\\UL=M+t \cdot s_M = 840+350=1190

The 95% confidence interval for the mean difference is (490, 1190).

7 0
3 years ago
Ricky completely filled a bucket to wash his car. After he finished Washing the car, 5/8 of the water remained in the bucket. Wr
igomit [66]
1-5/8=3/8
If he had 5/8 leftover, then he used 3/8.
6 0
4 years ago
Which ordered pair is a solution of the equation?<br><br> y=−2x+5
RUDIKE [14]

Answer:

10 is your answer

4 0
3 years ago
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