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3 years ago

If an impulse travels 100 m/s, about how long will it take the impulse to travel 10 meters?

Mathematics

2 answers:

PtichkaEL [24]3 years ago

6 0

Answer:

0.1 seconds

Step-by-step explanation:

10/100=0.1

pentagon [3]3 years ago

5 0

Answer:

1/10th of a second or .1seconds

Step-by-step explanation:

100m/s meaning its traveling 100 meters a second.

Since its going to travel 10 meters, it will take 1/10 the time since 10/100 = 1/10

The time is in seconds so it will take them 1/10th of a second.

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Step-by-step explanation:

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2 years ago

Perform the indicated operation. Be sure the answer is reduced.

avanturin [10]

<h3>Given Equation:-</h3>

$\boxed{ \rm \frac{4x^{2}y^{3}z}{9} \times \frac{45y}{8 {x}^{5} {z}^{5} }}$

<h3>Step by step expansion:</h3>

$\dashrightarrow \sf\dfrac{4x^{2}y^{3}z}{9} \times \dfrac{45y}{8 {x}^{5} {z}^{3} }$

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$\dashrightarrow \sf\dfrac{ \cancel4x^{2}y^{3}z}{9} \times \dfrac{45y}{ \cancel8 {x}^{5} {z}^{3} }$

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$\dashrightarrow \sf\dfrac{x^{2}y^{3}z}{9} \times \dfrac{45y}{2{x}^{5} {z}^{3} }$

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$\dashrightarrow \sf\dfrac{x^{2}y^{3}z}{ \cancel9} \times \dfrac{ \cancel{45}y}{2{x}^{5} {z}^{3} }$

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$\dashrightarrow \sf\dfrac{x^{2}y^{3}z}{1} \times \dfrac{5y}{2{x}^{5} {z}^{3} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{x^{0}y^{3}z}{1} \times \dfrac{5y}{2{x}^{5 - 2} {z}^{3} }$

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$\dashrightarrow \sf\dfrac{y^{3}z}{1} \times \dfrac{5y}{2{x}^{3} {z}^{3} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{y^{3}z {}^{0} }{1} \times \dfrac{5y}{2{x}^{3} {z}^{3 - 1} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{y^{3}}{1} \times \dfrac{5y}{2{x}^{3} {z}^{2} }$

$\\ \\$

$\dashrightarrow \sf \dfrac{5y \times {y}^{3} }{2{x}^{3} {z}^{2} }$

$\\ \\$

$\dashrightarrow \sf \dfrac{5y {}^{0} \times {y}^{3 + 1} }{2{x}^{3} {z}^{2} }$

$\\ \\$

$\dashrightarrow \sf \dfrac{5 \times {y}^{4} }{2{x}^{3} {z}^{2} }$

$\\ \\$

$\dashrightarrow \bf \dfrac{5 {y}^{4} }{2{x}^{3} {z}^{2} }$

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$\therefore \underline{ \textbf{ \textsf{option \red c \: is \: correct}}}$

8 0

2 years ago

Evaluate M^2 /p^2 for M = 10, N =-5p and P = -2

kondaur [170]

<u>Answer: </u>

The solution of $\bold{\frac{M^{2}}{P^{2}}}$ for M = 10, N = -5P and P = -2 is 25

<u>Solution: </u>

From question, given that the value of M is 10 and N is -5p and P is -2

We have to evaluate the value of $\frac{M^{2}}{P^{2}}$ ,

By substituting the values of M and N, we get

$\frac{M^{2}}{P^{2}} = \frac{10^{2}}{(-2)^{2}}$

Expanding $\bold{10^{2}}$ :

Here 10 is the base value and 2 is the exponent value. So the base term 10 is multiplied by itself two times.

$10^{2} = 10 \times 10 = 100$

Similarly expanding $\bold{(-2)^{2}}$ :

Here -2 is the base term and 2 is the exponent value. So the base term -2 is multiplied by itself two times.

$(-2)^{2} = -2 \times -2 = 4$

So the equation $\frac{M^{2}}{P^{2}} = \frac{10^{2}}{(-2)^{2}}$ becomes,

$\frac{M^{2}}{P^{2}} = \frac{100}{4}$

By dividing 100 by 4 , we get the result as 25

Hence the solution of $\bold{\frac{M^{2}}{P^{2}}}$ when M = 10 and P = -2 is 25

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