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Slav-nsk [51]
3 years ago
5

Vinny decorated 72 cookies and 36 minutes how many cookies did you decorate per minute

Mathematics
1 answer:
SCORPION-xisa [38]3 years ago
6 0
2 cookies. 72/36= 2 cookies per minute. 
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Find the median of the following numbers. 14, 17, 21, 28, 40. ​
Elis [28]

Answer:21

Step-by-step explanation: The median is the number in the middle sorted from least to greatest, here 21 is the middle number.

4 0
4 years ago
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Which of the following rules describes the pattern in the table?
sattari [20]

Answer:

b = e + 4

b = e + 4 i think that is the pattern in the table

6 0
3 years ago
While grading her students' most recent quiz on equation solving, Mrs. Jones calculated that approximately forty percent of her
EastWind [94]

The given equation is,

3(-n+4)+5n=2n

Part 1:

Solve the above equation for n.

Using distributive property of multiplication,

\begin{gathered} -3n+3\times4+5n=2n \\ -3n+12+5n=2n \end{gathered}

Now, group the like terms.

-3n+5n-2n+12=0

Now, add the like terms.

\begin{gathered} -5n+5n+12=0 \\ 0=-12 \end{gathered}

0=-12 is a false statement.

Since we obtained a false statement, the given equation has no solution.

So, option b is correct.

Part 2:

The option (a) is n=3.

If while solving an equation, a single value is obtained for the variable, then the equation has only a single solution. If n=3 is obtained after solving the equation, then the student should chose option (a) as the answer.

The option (b) is "no solution".

While solving an equation, if we obtain an equation which is mathematically false, then the equation will have no solution. So, no solution is chosen when no value is obtained for n and the final equation is mathematically false.

The option (c) is "infinitely many solutions".

While solving an equation, if we obtain an equation which is mathematically correct such as 0=0, 7=7 etc., then the equation will have infinietly many solutions. So, infinitely many solutions is chosen when no value is obtained for n and the final equation is mathematically correct.

8 0
1 year ago
(4x + 4)(ax – 1) – x2 +4
Oksana_A [137]

Answer:

b=-3

Step-by-step explanation:

If the expression simplifies to bx that means the x^{2} terms and the constant terms must be cancel out.

Simplify it first.

(4x+4)(ax-1)-x^{2} +4\\=(4ax^{2} -4x+4ax-4)-x^{2} +4\\=4ax^{2} -x^{2} -4x+4ax-4+4\\=4ax^{2} -x^{2} -4x+4ax

We know –4 + 4 will cancel out. If we simplify this expression to only an x term, then the x^{2} terms should be cancelled. Therefore, we say that 4ax^2 – x^2 = 0.

4ax^{2} -x^{2} =0\\x^{2} (4a-1)=0\\4a-1=0\\4a=1\\a=\frac{1}{4}

If we put a = ¼, then we can find the value of b:

=4(\frac{1}{4} )x^{2} -x^{2} -4x+4(\frac{1}{4} )x\\=x^{2} -x^{2} -4x+x\\ (cancel out x^{2} terms)\\

=-3x

bx=-3x\\      if the  expression is equivalent to bx

Therefore, b = –3.

8 0
3 years ago
2. Saul invested an average of $425 per month since age 30 in various securities for his
BabaBlast [244]

Answer:

$507.30

Step-by-step explanation:

-Given the monthly deposits are $425 and the interest rate is 3.5% for 30 years.

-The amount of the investment after 30 years is calculated as;

A=P(1+i/n)^n, n=time \ in \ months\\\\=425(1+0.035/12)^{30\times 12}\\\\=1212.65

-Assuming Saul started saving at age 20, his investment term will be 40 yrs.

-His investment amount is thus:

A=P(1+i/n)^n, n=time \ in \ months\\\\=425(1+0.035/12)^{40\times 12}\\\\=1719.95

#We subtract to find how much more he would have if he started saving at 20;

=A_{20}-A_{30}\\\\=1719.95-1212.65\\\\=507.30

Hence, Saul would have $507.30 more had he started saving 10 years earlier.

5 0
4 years ago
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