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sergejj [24]
3 years ago
6

Homework was confusing today! please explain and verify your answer!​

Mathematics
1 answer:
erik [133]3 years ago
7 0

Answer:

14 days

Step-by-step explanation:

one third of 42  is 42/3 = 14

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In a survey of randomly selected 3,900 family-owned businesses with revenues exceeding $1 million a year, it was found that 1,91
Maurinko [17]

Answer:

a) The 90% confidence interval to estimate the proportion of family-owned businesses without strategic business plans is (0.4768, 0.5032). This means that we are 90% sure that the true proportion of all family-owned businesses without strategic business plans is between these two values.

b) Wider

Step-by-step explanation:

Question a:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the z-score that has a p-value of 1 - \frac{\alpha}{2}.

In a survey of randomly selected 3,900 family-owned businesses with revenues exceeding $1 million a year, it was found that 1,911 of them had no strategic business plan.

This means that n = 3900, \pi = \frac{1911}{3900} = 0.49

90% confidence level

So \alpha = 0.1, z is the value of Z that has a p-value of 1 - \frac{0.1}{2} = 0.95, so Z = 1.645.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.49 - 1.645\sqrt{\frac{0.49*0.51}{3900}} = 0.4768

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.49 + 1.645\sqrt{\frac{0.49*0.51}{3900}} = 0.5032

The 90% confidence interval to estimate the proportion of family-owned businesses without strategic business plans is (0.4768, 0.5032). This means that we are 90% sure that the true proportion of all family-owned businesses without strategic business plans is between these two values.

Question b:

The margin of error is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

The higher the confidence level, the higher the value of z, thus the higher the margin of error and the interval is wider. Thus, a 99% confidence interval is wider than a 90% confidence interval.

3 0
3 years ago
Help on college algebra, question is on the picture!
kodGreya [7K]
\frac{7x+1}{x-2} + \frac{2}{x} = \frac{-4}{ x^{2} -2x} is given 
here , \frac{7x+1}{x-2} + \frac{2}{x} = \frac{-4}{ x^{2} -2x} 
or, \frac{7x^{2} +x +2x-4 }{x(x-2)} = \frac{-4}{ x^{2} -2x}
or,\frac{7 x^{2} +3x-4}{ x^{2} -2x} = \frac{-4}{ x^{2} -2x}
or,7x²+3x-4=-4
or,7x²+3x=0
or,x(7x+3)=0
Either,x=0| Or,7x+3=0
                |or,7x=-3
                |or,x=\frac{-3}{7}
So , the solution set is S={0,-\frac{3}{7}}
8 0
3 years ago
The image shows a geometric representation of the function f(x)=x^2-2x-6 written in standard form. What is the function written
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Y=(x-1)^2-7 This is this function in vertex form
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It took the race car 22 minutes to travel 114.4 kilometers. At what rate did the car travel? Use the formula r=d/t where r is th
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Answer:

5.2 Km/Min

Step-by-step explanation:

Speed/Rate= Distance/Time

Speed/Rate = 114.4/22

Speed/Rate = 5.2 KM/min

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In right triangle AABC,<br> MZA= 37º. Find mzB.<br> 1
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53 degrees
Because 180 - 90 ( right angle ) - 37 = 53
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