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Fantom [35]
2 years ago
6

Find the area of the kite

Mathematics
1 answer:
dexar [7]2 years ago
4 0

Given:

A figure of a kite.

To find:

The area of the given kite.

Solution:

The area of a kite is the half of the product of its diagonals.

A=\dfrac{d_1d_2}{2}             ...(i)

Where, d_1,d_2 are two diagonals of the kite.

From the given figure it is clear that the length of one diagonal is the sum of 12 and 8.

d_1=12+8

d_1=20

Let the second diagonal be 2x. The first diagonals bisect the second diagonal. So, the length of one parts of the diagonal is x.

Diagonals of a kite are perpendicular to each other. Using Pythagoras theorem, we get

Hypotenuse^2=Perpendicular^2+Base^2

13^2=x^2+12^2

169-144=x^2

25=x^2

5=x

The length of second diagonal is:

d_2=2x

d_2=2(5)

d_2=10

Substituting d_1=20,d_2=10 in (i), we get

A=\dfrac{20\times 10}{2}

A=\dfrac{200}{2}

A=100

Therefore, the area of the kite is 100 square units.

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3 years ago
I need to find measure of angle "u" m
garik1379 [7]

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TW UV

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