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tangare [24]
3 years ago
14

Dennis has less than 70 min. to spend on some homework questions. He spent 10 min. on the first two questions. The rest of the q

uestions will take 5/2 min. each
What statement describes the solution to this inequality?

A. Dennis can complete less than 24 questions.
B. Dennis can complete fewer than 60 questions.
C. Dennis can complete fewer than 32 questions.
D. Dennis can complete fewer than 4 questions.
Mathematics
2 answers:
AlexFokin [52]3 years ago
7 0
Dennis can complete 24

HOEP THIS HELPED!
Mrrafil [7]3 years ago
5 0

Answer:

A. Dennis can complete less than 24 questions.

Step-by-step explanation:

Let x represent the remaining number of questions to be completed.  He can complete each of them in 5/2 minutes each; this gives us the expression 5/2x.

He has already spent 10 minutes; this gives us 5/2x+10.

He has less than 70 minutes to spend; this gives us the inequality

5/2x+10<70

Subtract 10 from each side:

5/2x+10-10 < 70-10

5/2x < 60

Divide both sides by 5/2:

5/2x÷5/2 < 60÷5/2

x < 60/1 ÷ 5/2

To divide fractions, flip the second one and multiply:

x < 60/1 × 2/5

x < 120/5

x < 24

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vovangra [49]

The <em>cost of the jacket</em> purchased using the <em>System of equation</em> is $46.16

<u>Given the cost prices</u> :

  • Total cost = $95.11
  • Cost of shoes = x
  • Cost of jacket = x - 2.79

<u>We could set up an equation relating the cost of each item to the total Cost : </u>

<em>Total cost = cost of jacket + cost of shoes</em>

95.11 = x - 2.79 + x

95.11 = 2x - 2.79

95.11 + 2.79 = 2x

97.90 = 2x

x = 97.90 / 2

x = 48.95

Cost of jacket = $48.95 - 2.79 = $46.16

Therefore, Cost of jacket is $46.16

Learn more : brainly.com/question/24938959

8 0
2 years ago
the sun shines on a flagpole, causing a shadow to be cast on the ground. the distance from the base of the pole to the tip of th
kobusy [5.1K]

Answer:

30.17feet high

Step-by-step explanation:

Given the following

the distance from the base of the pole to the tip of the shadow = 49feet (hypotenuse)

angle of elevation = 38°

Required

Height of the flagpole (opposite)

Using the SOH CAH TOA identity

Sin theta = opposite/hypotenuse

Sin 38 = H/49

H = 49sin38

H = 49(0.6157)

H = 30.17feet

Hence the flagpole is 30.17feet high

7 0
3 years ago
Given: ΔАВС, m∠ACB = 90°,m∠ACD = 30°,AD = 8 cm. Find: CD, Perimeter ΔABC <br><br> Please solve!
sukhopar [10]
If m ACD = 30 => m DCB = 60.
In triangle ACD:
sin 30^{o}=sin  \frac{AD}{AC} =\ \textgreater \   \frac{1}{2}  =  \frac{8}{AC} =\ \textgreater \  AC=16&#10;
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BC= 16\sqrt{3}
AC^{2}+CB^{2}=AB^{2} => AB=\sqrt{1024}=32.
=> P=16+32+16 \sqrt{3}=48 +16 \sqrt{3}.

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densk [106]
Hi,

John haves 99 stickers. If Sally gave him 36 more that means john haves 99 + 36 = 135 more stickers than Sally.

Hope this helps.
r3t40
5 0
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Answer:

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