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4 years ago

How many times does 21 go into 457 with a remainder

Mathematics

2 answers:

kvv77 [185]4 years ago

8 0

Answer:

21 r16

Step-by-step explanation:

Gre4nikov [31]4 years ago

7 0

Answer:

21 goes into 457 21 times with a remainder of 16

Step-by-step explanation:

You divide 457 by 21, you get a decimal of 21. Multiply 21 times 21 and subtract your answer from 457. This gives you the remainder of 16

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At a play, 117 tickets were sold. Adult tickets cost 2.50 and children’s tickets cost 1.00. In all 243$ was taken in. How many o

Agata [3.3K]

Answer:

Adult tickets = 84

Children tickets = 33

Step-by-step explanation:

At a play 117 tickets were sold.

Adult's tickets (a) cost $2.50 each and,

Children's (c) tickets cost $1.00 each

Money collected = $243

This is the simultaneous equation formed:

a + c = 117 ... (i)

2.5a + c = 243 ... (ii)

Subtracting (ii) - (i) we get;

1.5a = 126

a = 126 ÷ 1.5 = 84

So there were 84 adult's tickets sold and 117 - 84 = 33 children's tickets sold.

7 0

3 years ago

Will crown the correct answers brainliest 3x

Solnce55 [7]

Answer :

(1) $\frac{1}{x}+\frac{1}{y}=\frac{y+x}{xy}$

(2) $\frac{1}{5x}+\frac{1}{3y}=\frac{3y+5x}{15xy}$

(3) $\frac{1}{7x}-\frac{1}{2y}=\frac{2y-7x}{14xy}$

(4) $\frac{2}{5x}+\frac{3}{7y}=\frac{6y+15x}{21xy}$

(5) $\frac{7}{11x}-\frac{1}{33y}=\frac{231y-11x}{363xy}$

(6) $\frac{1}{2x}+\frac{3}{x}-\frac{1}{7y}=\frac{7y+42y-2x}{14xy}$

Step-by-step explanation :

(1) The given expression is: $\frac{1}{x}+\frac{1}{y}$

$\frac{1}{x}+\frac{1}{y}=\frac{y+x}{xy}$

(2) The given expression is: $\frac{1}{5x}+\frac{1}{3y}$

$\frac{1}{5x}+\frac{1}{3y}=\frac{3y+5x}{(5x)\times (3y)}=\frac{3y+5x}{15xy}$

(3) The given expression is: $\frac{1}{7x}-\frac{1}{2y}$

$\frac{1}{7x}-\frac{1}{2y}=\frac{2y-7x}{(7x)\times (2y)}=\frac{2y-7x}{14xy}$

(4) The given expression is: $\frac{2}{5x}+\frac{3}{7y}$

$\frac{2}{5x}+\frac{3}{7y}=\frac{(2\times 3y)+(3\times 5x)}{(5x)\times (7y)}=\frac{6y+15x}{21xy}$

(5) The given expression is: $\frac{7}{11x}-\frac{1}{33y}$

$\frac{7}{11x}-\frac{1}{33y}=\frac{(7\times 33y)-(1\times 11x)}{(11x)\times (33y)}=\frac{231y-11x}{363xy}$

(6) The given expression is: $\frac{1}{2x}+\frac{3}{x}-\frac{1}{7y}$

$\frac{1}{2x}+\frac{3}{x}-\frac{1}{7y}=\frac{(x\times 7y)+(3\times 2x\times 7y)-(2x\times x)}{(2x)\times (x)\times (7y)}=\frac{7xy+42xy-2x^2}{14x^2y}=\frac{7y+42y-2x}{14xy}$

7 0

3 years ago

Simplify this question

Lera25 [3.4K]

Answer:

decimal form: 1.88982236505

Hope This Helps! Have A Nice Day!!

4 0

4 years ago

Seth’s father is thinking of buying his son a six-month movie pass for $40. With the pass, matinees cost $1.00. If matinees are

Ymorist [56]

Answer:

In order for it to benefit his father to buy the pass Seth have to attend the movies for 11 times.

Step-by-step explanation:

Given:

Cost of movie pass = $40

Cost per matinees with pass = $1.00

Cost per matinees without pass = $3.50

To Find:

Number of times must Seth attend in order for it to benefit his father to buy the pass = ?

Solution:

Let x be the number of times he wants to visit

To profit his father

The number of visits without pass = the number of visits with passin the cost of $3.50

Then, without pass if he visits for x times then the cost will be = 3.50x

Also with pass, the number of times he can visit the pass = $\frac{40}{3.50}$

then

$\frac{350 x}{3.50} = \frac{40}{3.50}$

$3.50x = 40$

$x = \frac{40}{3.50}$

x = 11.42

x = 11 (approx)

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4 years ago

PLEASE HELP THIS IS DUE ASAP AND I WILL MARK U BRAINLIEST

suter [353]

Answer: 4/1

Step-by-step explanation:

Rise over run. Starting at 1 on the y axis this line moves up 4 and over (right) 1 before it hits 1 on the x axis.

7 0

3 years ago