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bogdanovich [222]
4 years ago
12

Find the gcf for the list. 28y4, 20y3

Mathematics
1 answer:
blagie [28]4 years ago
3 0
GCF of 28y^4 and 20y^3 is 4y^3
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If 25 tickets cost $50, find the cost of 1 ticket ​
Fudgin [204]

Answer:

<h2><em>$</em><em>2</em></h2>

<em>solution \\ cost \: of \: 25 \: ticket = 50 \\ cost \: of \: one \: ticket =  \frac{50}{25}  \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  = 2</em>

<em>hope </em><em>this </em><em>helps.</em><em>.</em>

<em>Good </em><em>luck</em><em> on</em><em> your</em><em> assignment</em>

3 0
4 years ago
Read 2 more answers
Just cant wrap my head around this, I'm trying to focus on the more difficult question and this is just hurting my brain. I need
Inessa [10]

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step elementary school of the frog said april

7 0
3 years ago
G(r)=−(r+11)(r+14)
Oduvanchick [21]

Answer:

The zeros are

Larger r=-11

Smaller r=-14

2)The vertex is (-12.5,-2.25)

Step-by-step explanation:

The given function is:

g(r)=(r+11)(r+14)

This function is already in the factored form therefore it is easy to find the zeros,

(r+11)(r+14)=0

Either (r+11)=0 or (r+14)=0

The zeros are r=-14 or r=-11

b) The expanded form of the given function is:

g(r)=r^2+25r+154

We obtain the vertex form by completing the square:

g(r)=r^2+25r+(\frac{25}{2})^2+154-(\frac{25}{2})^2

The vertex form is:

g(r)=(r+\frac{25}{2})^2-(\frac{9}{4}

Therefore the vertex is (-12.5,-2.25)

8 0
3 years ago
Solve x2 - 16 = 59. What does x<br> equal?
nikklg [1K]

Answer:

37.5

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Answer asap please!!
morpeh [17]
60.
Multiply
3 by 20.
You can do this on paper,
20
x
3
____
60
Multiply the ones spot first, 0 x 3 is 0 so add that in your ones spot, then go 2x3 since nothing is under to, just go to 3 and you’ll get 6, which you add to the tens spot.
Have a good day!
6 0
3 years ago
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