Given :-
- Two triangles with their two angles equal .
To Find :-
Answer :-
Here in ∆ABC and ∆EDC ,
CAB = CED (given )- CBA = CDE (given)
Therefore by AA similarity criterion , we can say that ∆ABC ~ ∆EDC . Also we know that corresponding sides of similar triangles are proportional . So ,
→ AC/EC = BC/DC
→ AC/9 = 8/12
→ AC = 8/12 * 9
→ AC = 6
<u>Hence</u><u> the</u><u> </u><u>measure</u><u> of</u><u> </u><u>side </u><u>AC </u><u>is </u><u>6</u><u> </u><u>.</u>
I hope this helps.
Answer:
111°
Step-by-step explanation:
The two angles are alternate exterior angles, and those types of angles are always congruent if there are parallel lines.
Answer:
5.7 I pretty sure
Step-by-step explanation:
Answer:
I got 18 as my answer
Step-by-step explanation:
I made a triangle with the right side by dropping a vertical. Lets call the point straight down from C, E
Then I found the angle of D
sin θ = 5/13
θ = sin-¹(5/13)
θ≅22.619°
Then I found length of DE by
cosθ (remember we know what theta is) = X/13
12cosθ = X
X = 12
The length of DE is 12.
Since AD is 30, and the left side has two right angles we can do
AD - DE to find BC.
30-12 is 18
It's A. all you need to do is plug in the "n"-values for each equation and see if it is true. the only one that works is answer A.
