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Triss [41]
3 years ago
5

Write the ordered pair that represents YZ. Then find the magnitude of YZ. y(-4,12), Z(1,19).

Mathematics
2 answers:
ki77a [65]3 years ago
6 0

The magnitude of YZ is 8.6

<u>Explanation:</u>

<u />

Y( -4, 12)

Z ( 1, 19)

Magnitude of YZ = ?

We know:

YZ = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

On substituting the value we get:

YZ = \sqrt{(1+4)^2 + (19 - 12)^2} \\\\YZ = \sqrt{(5)^2 + (7)^2} \\\\YZ = \sqrt{25+49} \\\\YZ = \sqrt{74} \\\\YZ = 8.6

Thus, the magnitude of YZ is 8.6

Maurinko [17]3 years ago
3 0

Answer:

its <5,7> \sqrt{74}

Step-by-step explanation:

when you put it into edge, you can write it as <5,7> sqrt 74

and it will mark it correct.

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Softa [21]

Answer:

y = 17x - 55

Step-by-step explanation:

Convert the coordinates in point-slope form:

y + 4 = 17(x -3)

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y = 17x - 55

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5 0
3 years ago
A seafood company sells salmon and shrimp to local restaurants. The company charges its customers for one price for salmon and a
Romashka [77]

Answer:

salmon per pound is $16.68

shrimp per pound is $6.71

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166.63/10=16.68

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3 0
3 years ago
OFFERING 50 POINTS!!! The army reports that the distribution of waist sizes among female soldiers is approximately normal, with
hammer [34]

Answer:

Step-by-step explanation:

1)

Percentile is related to the area under the standard normal curve to the LEFT of a certain data value (which in this case would be 26.1 inches).

On my Texas Instruments TI-83 Plus calculator, I found this area as follows:

normcdf(-100, 26.1, 28.4,1.2), where the range -100 to 26.1 represents the area (as a decimal fraction) to the left of 26.1 inches.  My result was 0.028, which corresponds to the 3rd percentile (0.028 rounds off to 0.03, which would be 3rd percentile).

2)  The mean waist size is 28.4 inches, represented by a vertical line through the standard normal curve lying between 24 and 32.  We use the same function on the calculator:  normcdf(24, 32, 28.4, 1.2).

The result is 0.9985.  Subtracting this from 1.0000, we get 0.001, or 0.1%, which is the percentage of female soldiers requiring custom uniforms.

4 0
2 years ago
The weights of newborn baby boys born at a local hospital are believed to have a normal distribution with a mean weight of 3903
polet [3.4K]

Answer:

0.9861 = 98.61% probability that the weight will be less than 4884 grams.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean weight of 3903 grams and a standard deviation of 446 grams.

This means that \mu = 3903, \sigma = 446

If a newborn baby boy born at the local hospital is randomly selected, find the probability that the weight will be less than 4884 grams.

P-value of z when X = 4884. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{4884 - 3903}{446}

Z = 2.2

Z = 2.2 has a p-value of 0.9861

0.9861 = 98.61% probability that the weight will be less than 4884 grams.

7 0
3 years ago
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