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Triss [41]
3 years ago
5

Write the ordered pair that represents YZ. Then find the magnitude of YZ. y(-4,12), Z(1,19).

Mathematics
2 answers:
ki77a [65]3 years ago
6 0

The magnitude of YZ is 8.6

<u>Explanation:</u>

<u />

Y( -4, 12)

Z ( 1, 19)

Magnitude of YZ = ?

We know:

YZ = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

On substituting the value we get:

YZ = \sqrt{(1+4)^2 + (19 - 12)^2} \\\\YZ = \sqrt{(5)^2 + (7)^2} \\\\YZ = \sqrt{25+49} \\\\YZ = \sqrt{74} \\\\YZ = 8.6

Thus, the magnitude of YZ is 8.6

Maurinko [17]3 years ago
3 0

Answer:

its <5,7> \sqrt{74}

Step-by-step explanation:

when you put it into edge, you can write it as <5,7> sqrt 74

and it will mark it correct.

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Graph the circle (x+6)^2 + (y+5)^2 =9
Andrei [34K]

Answer:

This a circle centered at the point (-6,-5), and of radius "3" as it is shown in the attached image.

Step-by-step explanation:

Recall that the standard formula for a circle of radius "R", and centered at the point (x_0,y_0) is given by:

(x-x_0)^2+(y-y_0)^2=R^2

Therefore, in our case, by looking at the standard equation they give us, we extract the following info:

1)  R^2 = 9\,\,\,then\,\,\,R=3  since the radius must be a positive number and (R=-3) is not a viable answer.

2) x_0=-6    for ( x-x_0) to equal   (x+6)

3) y_0=-5    for ( y-y_0) to equal   (y+5)

Therefore, we are in the presence of a circle centered at the point (-6,-5), and of radius "3". That is what we draw as seen in the attached image.

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3 years ago
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2 years ago
How do you find the height of a triangle (to calculate area)?
Lilit [14]

Answer:

The height of the triangle could be found by the <u>Pythagoras theorem</u>, where the result is, with the data of the exercise:

  • <u>Height of the triangle = 10.392</u>

And the area of the triangle is:

  • <u>Area of the triangle = 31.176 units^2</u>

Step-by-step explanation:

When you have two measurements of a triangle, as the case in the picture, you can find the third with the <em>Pythagoras theorem</em>, which is:

  • <u>(opposite leg)^2 + (adjacent leg)^2 = hypotenuse^2</u>

As you can see in the picture, the measurement of the hypotenuse is 12, and the opposite leg could be 6, for this reason, we're gonna clear the adjacent leg of the formula above:

  • (opposite leg)^2 + (adjacent leg)^2 = hypotenuse^2
  • (adjacent leg)^2 = hypotenuse^2 - (opposite leg)^2

Now, we can replace the values in the formula obtained:

  • (adjacent leg)^2 = hypotenuse^2 - (opposite leg)^2
  • (adjacent leg)^2 = 12^2 - 6^2
  • (adjacent leg)^2 = 144 - 36
  • (adjacent leg)^2 = 108

Now, as we just need the adjacent leg, we take the square root of both sides:

  • adjacent leg = \sqrt{108}
  • <u>adjacent leg = 10.392 approximately</u>.

Now, with these data, we can find the area of the triangle with the next formula:

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  • And we replace the measurements:
  • Area of a triangle = (6 * 10.392) / 2
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As the image does not contain units, it would be simply this number, however, <em>you should know that the area units are usually given squared, for example: in^2 or ft^2</em>.

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