Consider any point P(x, y) in the coordinate axis.
The reflection of this point across the y-axis is the point P'(-x, y).
(x, y) and (-x, y) are the 'mirror' images of each other, with the y'axis as the 'mirror'.
For example the coordinates of the image of P(4, 13) after the reflection across the y-axis is P'(-4, 13)
or, if P(-5, -9), then P'(5, -9)
Answer: if coordinates of V are (h, k), coordinates of V' are (-h, k)
Answer:
The ordered pair is a solution to the equation
Step-by-step explanation:
Plug the ordered pair into the equation as (x,y):
y = -x + 8
4 = -4 + 8
4 = 4
Since both sides are equal to each other, then the ordered pair is a solution to the equation.
Answer:
Step-by-step explanation:
i don't know how to show you the graph so i took a screenshot on my computer of the graph and post it up for you
Answer:
10
Step-by-step explanation:
Substitute n for 10, 11 and 13
45 - 10 = 35
45 - 11 = 34
45 - 12 = 33
The answer is ten because when substituting n for 10, the equation
35 = 45 - 10
is true
The only way 3 digits can have product 24 is
1 x 3 x 8 = 241 x 4 x 6 = 242 x 2 x 6 = 242 x 3 x 4 = 24
So the digits comprises of 1,3,8 or 1,4,6, or 2,2,6, or 2,3,4
To be divisible by 3 the sum of the digits must be divisible by 3.
1+ 3+ 8=12, 1+ 4+ 6= 11, 2 +2 + 6=10, 2 +3 + 4=9Of those sums of digits, only 12 and 9 are divisible by 3.
So we have ruled out all but integers whose digits consist of1,3,8, and 2,3,4.
Meanwhile they must be odd they either must end in 1 or 3.
The only ones which can end in 1 are 381 and 831.
The others must end in 3.
They must be greater than 152 which is 225. So the
First digit cannot be 1. So the only way its digits can contain of1,3,8 and close in 3 is to be 813.
The rest must contain of the digits 2,3,4, and the only way they can end in 3 is to be 243 or 423.
So there are precisely five such three-digit integers: 381, 831, 813, 243, and 423.
