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3 years ago

8

Lilly saw a jelly fish at 6 feet below sea level. She saw a bright blue fish at 10 feet below sea level. What is the distance be

tween the blue fish and the jelly fish?

1 answer:

Greeley [361]3 years ago

3 0

Answer:

4 feet of distance between each other it is very simple and easy.

Step-by-step explanation:

They are both 6 feet and 10 feet away from each other so you just take 10-6 which is 4

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photoshop1234 [79]

Answer:

1. 1/1 , 1, 100%

2. 1/2, 0.5, 50%

3. 1/3, 0.3, 30%

4. 2/3, 0.6, 60%

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6. 3/4, 0.75, 75%

7. 1/5, 0.2, 20%

8. 2/5, 0.4, 40%

9. 3/5, 0.6, 60%

10. 4/5, 0.8, 80%

11. 1/6, 0.16, 16%

12. 5/6, 0.83, 83%

13. 1/8, 0.125, 12.5%

14. 3/8, 0.375, 37.5%

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2 years ago

Jenna jump 156 inches in the long jump competition After High School track meet how many feet did Jenna jump

klio [65]

13 feet hears how:
156/12=13

divide it

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2 years ago

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Please help I would be very greatful. On a coordinate plane, a solid straight line has a positive slope and goes through (0, 0.2

Vlad1618 [11]

Answer:

Step-by-step explanation:

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3 years ago

A ball is launched straight up in the air from a height of 6 feet. Its velocity (feet/second) t seconds after launch is given by

german

Step-by-step explanation:

A ball is launched straight up in the air from a height of 6 feet. The velocity as a function of time t is given by :

f(t) = -32 t+285

Height of the ball is :

$h(t)=\int\limits{f(t){\cdot} dt}\\\\h(t)=\int\limits{(-32t+285){\cdot} dt}\\\\h(t)=-16t^2+285t+C$

C is constant. Here the ball is launched from a height of 6 feet. So,

$h(t)=-16t^2+285t+6$

At t = 2 s, $h(t)=-16(2)^2+285(2)+6=512\ m$

At t = 9 s, $h(t)=-16(9)^2+285(9)+6=1275\ m$

Between 2 s and 9 s, the ball's height changed is : 1275 - 512 = 763 m.

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3 years ago

Write an equation in slope-intercept form with a

lora16 [44]

Your equation would be:
D. y = 10x + 6

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3 years ago