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3 years ago

8

Lilly saw a jelly fish at 6 feet below sea level. She saw a bright blue fish at 10 feet below sea level. What is the distance be

tween the blue fish and the jelly fish?

1 answer:

Greeley [361]3 years ago

3 0

Answer:

4 feet of distance between each other it is very simple and easy.

Step-by-step explanation:

They are both 6 feet and 10 feet away from each other so you just take 10-6 which is 4

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I cannot figure this out. Any help would be appreciated.

Lesechka [4]

So you are finding M
90+x+15+3x+15=180
4x=60
X = 15
LMN = 15+15
LMN = 30
hopefully this is correct :)

7 0

2 years ago

There are 18 stores in California and 12 stores in Nevada the shops opens 10 new stores some are in California, and some are in

Rzqust [24]

That means there would be 28 in California and still 12 in Nevada or if California takes from Nevada it would be California 28 and Nevada 2

4 0

3 years ago

What is 5047 divided by 52?

xenn [34]

Answer:

97.06

Step-by-step explanation:

5047 / 52

= 97.06

4 0

2 years ago

Read 2 more answers

Cual es resultado de 8.5 × 10^4 - 3.0 × 10^3

Veronika [31]

Simplify 10^4 to 10000

8.5x10000-3.0x10^3

Simplify 8.5x*10000 to 85000x
85000x-3.0*10^3
Simplify 3.0x10^3 to 3*10^3
Answer 85000x-3*10^3

5 0

3 years ago

Write an equation for an ellipse centered at the origin, which has foci at (\pm\sqrt{8},0)(± 8 ,0)(, plus minus, square root o

Alchen [17]

Answer:

The equation of ellipse centered at the origin

$\frac{x^2}{18} +\frac{y^2}{10} =1$

Step-by-step explanation:

given the foci of ellipse (±√8,0) and c0-vertices are (0,±√10)

The foci are (-C,0) and (C ,0)

Given data (±√8,0)

the focus has x-coordinates so the focus is lie on x- axis.

The major axis also lie on x-axis

The minor axis lies on y-axis so c0-vertices are (0,±√10)

given focus C = ae = √8

Given co-vertices ( minor axis) (0,±b) = (0,±√10)

b= √10

The relation between the focus and semi major axes and semi minor axes are $c^2=a^2-b^2$

$a^{2} = c^{2} +b^{2}$

$a^{2} = (\sqrt{8} )^{2} +(\sqrt{10} )^{2}$

$a^{2} =18$

$a=\sqrt{18}$

The equation of ellipse formula

$\frac{x^2}{a^2} +\frac{y^2}{b^2} =1$

we know that $a=\sqrt{18} and b=\sqrt{10}$

<u>Final answer:</u>-

<u>The equation of ellipse centered at the origin</u>

<u /> $\frac{x^2}{18} +\frac{y^2}{10} =1$ <u />

8 0

2 years ago

Read 2 more answers