1/3, 0,1,-2.....neither geometric or arithmetic
Answer:
FALSE
Step-by-step explanation:
A tessellation refest to a shape that is repeated over and over again covering a plane without any gaps or overlaps. The statement is false given that regular tessellations use only one polygon. Semi-regular tessellations are created with more than one type of regular polygon.
9514 1404 393
Answer:
4a. ∠V≅∠Y
4b. TU ≅ WX
5. No; no applicable postulate
6. see below
Step-by-step explanation:
<h3>4.</h3>
a. When you use the ASA postulate, you are claiming you have shown two angles and the side between them to be congruent. Here, you're given side TV and angle T are congruent to their counterparts, sides WY and angle W. The angle at the other end of segment TV is angle V. Its counterpart is the other end of segment WY from angle W. In order to use ASA, we must show ...
∠V≅∠Y
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b. When you use the SAS postulate, you are claiming you have shown two sides and the angle between them are congruent. The angle T is between sides TV and TU. The angle congruent to that, ∠W, is between sides WY and WX. Then the missing congruence that must be shown is ...
TU ≅ WX
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<h3>5.</h3>
The marked congruences are for two sides and a non-included angle. There is no SSA postulate for proving congruence. (In fact, there are two different possible triangles that have the given dimensions. This can be seen in the fact that the given angle is opposite the shortest of the given sides.)
"No, we cannot prove they are congruent because none of the five postulates or theorems can be used."
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<h3>6.</h3>
The first statement/reason is always the list of "given" statements.
1. ∠A≅∠D, AC≅DC . . . . given
2. . . . . vertical angles are congruent
3. . . . . ASA postulate
4. . . . . CPCTC
Answer:
15 ft
Step-by-step explanation:
Hi, the illustration for the problem is a right triangle with:
hypotenuse (C)= the length of the ladder = L
horizontal side(A) = distance from bottom of the ladder to the building = L - 6
vertical side(B) = distance from the top of the ladder to the bottom of the building = L - 3
So, we can use Pythagoras formula:
A2 +B2= C2
(L – 6 )² + (L-3)² = L²
L²-12L+36+L²-6L+9 =L²
L2 -18L+45 =0
APPLYING QUADRATIC FORMULA WE OBTAIN:
L =15 OR L=3
If L=3
Vertical side = L-3 = 0 (Length can´t be 0)
So L=15
Answer:
No.
Step-by-step explanation:
The answer is no because combining like terms on the same sign of the equal sign on the first side is 6n+9. on the other side you distribute 3 to the two numbers in the parenthesis getting 6n+27 and is not equal
