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Airida [17]
3 years ago
14

The radius of a sphere is 6 units

Mathematics
1 answer:
lesantik [10]3 years ago
7 0

Answer:

288 pi or 904.22

Step-by-step explanation:

(4/3) × pi × r³

(4/3) × pi × 6³

288pi or

288 × 3.14 = 904.32 units³

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Write the equation of a line, in slope-intercept form<br> (1,1);(-2,-11)<br> Y =
bonufazy [111]

Answer:

Y =4X  -3

Step-by-step explanation:

x1 y1  x2 y2

1 1  -2 -11

   

(Y2-Y1) (-11)-(1)=   -12  ΔY -12

(X2-X1) (-2)-(1)=    -3  ΔX -3

   

slope= 4          

B= -3          

   

Y =4X  -3    

6 0
3 years ago
Read 2 more answers
If The 3rd term of an A.S is and 5th term is . What is an A.P?​
guajiro [1.7K]

Answer:

you have to mention the 3rd term of AP and 5th term of AP. Then only we can find the AP.

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3 years ago
Exponentiation is the raising of one number to the power of another. This operation is performed using two asterisks **. Let's u
Harlamova29_29 [7]

In math, Exponentiation refers to the operation of raising one quantity to the power of another. See the program running the exponentiation below.

<h3>What is the required code?</h3>

The code is given below:

number_of_days = 30

amount_after_30days = 0.01 * (2 ** number_of_days)

# print the amount

print(amount_after_30days)

Learn more about exponentiation at;
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4 0
1 year ago
A rectangular field is 95 meters long and 65 meters wide. Give the length and width of another rectangular field that has the sa
Lena [83]

Answer:

There are a ton of answers. For instance, 1m by 159m.

Step-by-step explanation:

The formula for the area is a=l*w, where l and w are constants.

The formula for perimeter is p=2l+2w

The question wants another rectangle that has the same perimeter, but a smaller area.

The perimeter of the two fields has to be:

p=(2*95)+(2*65)\\p=190+130\\p=320

Thankfully, the question never specified how much smaller the area has to be. So let's go to the logical extreme and make it 1 meter wide. To conserve the perimeter, we'd have to add the removed 64 meters to the original 95 meters of length, resulting in a rectangle with a width of 1m and a length of 159m. This results in an area of exactly 159 m^{2}. The original rectangle had an area of 6175m^{2}. Mission accomplished!

But why stop there? Let's go even further down this rabbit hole!

Instead of 1, why don't we take it several steps further and use 0.0000001? At that point, the length would end up being  159.9999999m.

The area would be 0.00001599999999 m^{2}.

Let's go further!!

Width: 0.00000000000000000001

Length: 159.99999999999999999999

Area: 0.00000000000000000001599999999999999999999 (approximate).

One more, for old time's sake.

Width: 0.00000000000000000000000000000000000000000000000001m

Length: 159.99999999999999999999999999999999999999999999999999m

Area: 0.00000000000000000000000000000000000000000000000015999999999999999999999999999999999999999999999999999 m^{2}

At that point, there's so little area in the plot of land that you could claim it has no area!

5 0
2 years ago
admission to a carnival is $5 and each game at the carnival cost $0.85. you have $15 to spend on admission and games. what is th
aleksandrvk [35]
So, you have $15 in total to spend.

1. Subtract your admission fee. 15-5=10
2. Divide 10 by .85 to get the number of games you were able to play. 10 divided by .85 = 11.76
3. Now, since it says the minimum you were able to play, round to the nearest digit. 11.76=11

You were able to play a minimum of 1 game and a maximum of 11 games.
7 0
2 years ago
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