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anygoal [31]
3 years ago
5

Xavier worked 10 hours on Monday and 15 hours on Wednesday his total pay was $280 what was his rate per hour

Mathematics
2 answers:
mote1985 [20]3 years ago
5 0
11.2 is the awncer to the
FromTheMoon [43]3 years ago
4 0
$11.2
Hope this helps
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Convert 714.81 mm to meters. (please show the steps to how you did the problem.)
zaharov [31]

Answer:

0.7148 meter

Step-by-step explanation:

you have to divied 714.81 by 1000 to get 0.7148 meter

5 0
2 years ago
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Which of the following lists of ordered pairs is a function
devlian [24]

Answer:

d)(0,3), (-1,4), (1,6), (-1,7)

Step-by-step explanation:

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Chinese checkers is a game in which players move their pieces across a board using single moves or jumps like the traditional ga
DENIUS [597]
A. it is a hexagon (there are 6 sides) B. using the equation (n-2)180 (where n is the number of sides we get (6-2)180=4*180=720. divide 720 by 6 to get 120 for each angle of the hexagon. (it has no irregularities in it's shape so that number will be correct for them all.) C. to get that just divide 39 by 6 to get 6.5 in per side. Hope that helps:) 
6 0
3 years ago
1+-w2+9w and I need help cuz I’m on 76 and I’m sooo close help
Gnesinka [82]

\huge \boxed{\mathfrak{Question} \downarrow}

  • Simplify :- 1 + - w² + 9w.

\large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}

\large \sf1 + - w ^ { 2 } + 9 w

Quadratic polynomial can be factored using the transformation \sf \: ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), where \sf x_{1} and x_{2} are the solutions of the quadratic equation \sf \: ax^{2}+bx+c=0.

\large \sf-w^{2}+9w+1=0

All equations of the form \sf\:ax^{2}+bx+c=0 can be solved using the quadratic formula: \sf\frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.

\large \sf \: w=\frac{-9±\sqrt{9^{2}-4\left(-1\right)}}{2\left(-1\right)}  \\

Square 9.

\large \sf \: w=\frac{-9±\sqrt{81-4\left(-1\right)}}{2\left(-1\right)}  \\

Multiply -4 times -1.

\large \sf \: w=\frac{-9±\sqrt{81+4}}{2\left(-1\right)}  \\

Add 81 to 4.

\large \sf \: w=\frac{-9±\sqrt{85}}{2\left(-1\right)}  \\

Multiply 2 times -1.

\large \sf \: w=\frac{-9±\sqrt{85}}{-2}  \\

Now solve the equation \sf\:w=\frac{-9±\sqrt{85}}{-2} when ± is plus. Add -9 to \sf\sqrt{85}.

\large \sf \: w=\frac{\sqrt{85}-9}{-2}  \\

Divide -9+ \sf\sqrt{85} by -2.

\large \boxed{ \sf \: w=\frac{9-\sqrt{85}}{2}} \\

Now solve the equation \sf\:w=\frac{-9±\sqrt{85}}{-2} when ± is minus. Subtract \sf\sqrt{85} from -9.

\large \sf \: w=\frac{-\sqrt{85}-9}{-2}  \\

Divide \sf-9-\sqrt{85} by -2.

\large \boxed{ \sf \: w=\frac{\sqrt{85}+9}{2}}  \\

Factor the original expression using \sf\:ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right). Substitute \sf\frac{9-\sqrt{85}}{2}for \sf\:x_{1} and \sf\frac{9+\sqrt{85}}{2} for \sf\:x_{2}.

\large \boxed{ \boxed {\mathfrak{-w^{2}+9w+1=-\left(w-\frac{9-\sqrt{85}}{2}\right)\left(w-\frac{\sqrt{85}+9}{2}\right) }}}

<h3>NOTE :-</h3>

Well, in the picture you inserted it says that it's 8th grade mathematics. So, I'm not sure if you have learned simplification with the help of biquadratic formula. So, if you want the answer simplified only according to like terms then your answer will be ⇨

\large \sf \: 1 + -  w {}^{2}  + 9w \\  =\large  \boxed{\bf \: 1 -  {w}^{2}   + 9w}

This cannot be further simplified as there are no more like terms (you can use the biquadratic formula if you've learned it.)

4 0
2 years ago
Through: (3,5), slope=5\3
ANEK [815]
So slope intercpet form
y=mx+b

m=slope
b=y intercpet


slope=5/3
in (x,y) form

x=3
y=5 is one point


subsitute and solve for b
y=mx+b
5=5/3 times 3+b
5=3/3 times 5+b
5=1 times 5+b
5=5+b
subtract 5 from both sides
0=b

equation is
y=5/3x+0 or
y=5/3x
3 0
3 years ago
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