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vitfil [10]
2 years ago
14

Enter the ordered pair that is the solution to the system of equations graphed below.

Mathematics
1 answer:
dalvyx [7]2 years ago
6 0

Answer:

x = 5/2

y = -1/2

Step-by-step explanation:

if both equations start with 'y=' then set the expressions equal to each other

3/5x - 1 = x - 3

add 1 to each side to get:

3/5x = x - 1

subtract 5/5x from each side:

3/5x - 5/5x = -1

-2/5x = -1

multiply each side by -5/2:

x = 5/2

y = 2 1/2 - 3

y = -1/2

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(-y,x) --> (x,y)
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4 0
3 years ago
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For the function P(x) = x3 − 9x, at the point (2, −10), find the following. (a) the slope of the tangent to the curve (b) the in
Shalnov [3]

Answer:

3, in both a), b)

Step-by-step explanation:

a) The slope of the line tangent to the curve that passes through the point (2,-10) is equal to the derivative of p at x=2.

Using differentiation rules (power rule and sum rule), the derivative of p(x) for any x is p'(x)=3x^2-9. In particular, the value we are looking for is p'(2)=3(2^2)-9=12-9=3.

If you would like to compute the equation of the tangent line, we can use the point-slope equation to get y=3(x-2)-10=3x-16

b) The instantaneus rate of change is also equal to the derivative of P at the point x=2, that is, P'(2). This is equal to p'(2)=3.

4 0
3 years ago
Mason answers a question correctly in a trivia game and now has 0 points. The question was worth
zhannawk [14.2K]

Answer:

Mason recieved 15 points for answering the question correctly so that means that he had -15 points before. The points would be at -15 and 0.

8 0
3 years ago
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If you deposit $300 in an account with a 6% interest rate, how much will be in your account after 1 year? If you leave this mone
dolphi86 [110]

Answer:

I only know the first question, If you leave that money for 1 year it would equal $480 basically,  $300 x 1.6 = $480.

Step-by-step explanation:

5 0
2 years ago
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Find x when y = 32, given that x varies inversely as y, and x = 132 when y = 4.
gizmo_the_mogwai [7]

Answer:

When y=32, x=16.5

Step-by-step explanation:

Find x when y = 32, given that x varies inversely as y, and x = 132 when y = 4.

We are given:

x varies inversely with y

We can write it as: x\:\alpha \:\frac{1}{y}

x=\frac{k}{y}

We have x = 132, when y=4

We can find value of k by using these values

x=\frac{k}{y}\\132=\frac{k}{4}\\k=132*4\\k=528

We need to find x when y=32

x=\frac{k}{y}\\x=\frac{528}{32}\\x=16.5

So, when y=32, x=16.5

6 0
3 years ago
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