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kiruha [24]
3 years ago
8

Vita has a pice of rope that is 5 meters long. She cuts the rope into pieces that are each 1/3 meter long. How many pieces does

she cut?
Mathematics
1 answer:
sp2606 [1]3 years ago
4 0
Normally you would divide something like this by the cuts made. So if there were cuts of 2 inches on a 10 inch rope, then you should divide 10 by 2. It's the same with this:
5/ \frac{1}{3} = 5*3, 15 \ pieces
Multiply by the reciprocal when you are dividing fractions.
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PLSS help me with this and show your work
hodyreva [135]

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3x-1/5=x+1/3

3[3x-1]=5[x+1]

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9x-5x=5-3

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How do you do it?I'm lost
Leto [7]

Answer and Step-by-step explanation:

The way you complete this is by taking each points x and y and applying the translation. In this case the translation is x-7 and y+1.

Q's x and y are 1 , 1

R's x and y are 1 , 5

T's x and y are 5 , 1

S's x and y are 5 , 5

Now what you do is use the translation on all of these values.

Q's x and y turns into -6 , 2 (subtracted 7 to the 1 and added 1 to the 1)

R's x and y turns into -6 , 6

T's x and y are -2 , 2

S's x and y are -2 , 6

You can then plot the points on the graph and connect the lines to complete the reflection.

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Question 27<br><br> .........................................................
TiliK225 [7]

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3 years ago
if you roll a fair 6-sided die 9 times, what is the probability that at least 2 of the rolls come up as a 3 or a 4?
Kay [80]

Using the binomial distribution, it is found that there is a 0.857 = 85.7% probability that at least 2 of the rolls come up as a 3 or a 4.

For each die, there are only two possible outcomes, either a 3 or a 4 is rolled, or it is not. The result of a roll is independent of any other roll, hence, the <em>binomial distribution</em> is used to solve this question.

Binomial probability distribution

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

In this problem:

  • There are 9 rolls, hence n = 9.
  • Of the six sides, 2 are 3 or 4, hence p = \frac{2}{6} = 0.3333

The desired probability is:

P(X \geq 2) = 1 - P(X < 2)

In which:

P(X < 2) = P(X = 0) + P(X = 1)

Then

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{9,0}.(0.3333)^{0}.(0.6667)^{9} = 0.026

P(X = 1) = C_{9,1}.(0.3333)^{1}.(0.6667)^{8} = 0.117

Then:

P(X < 2) = P(X = 0) + P(X = 1) = 0.026 + 0.117 = 0.143

P(X \geq 2) = 1 - P(X < 2) = 1 - 0.143 = 0.857

0.857 = 85.7% probability that at least 2 of the rolls come up as a 3 or a 4.

For more on the binomial distribution, you can check brainly.com/question/24863377

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In-s [12.5K]

Answer:

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Step-by-step explanation:

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