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Natalka [10]
3 years ago
7

The two cones are similar. The smaller cone has a surface area of 11.74 inches2. Complete the last step to determine the surface

area of the larger cone. The scale factor of the larger to the smaller is , or . The surface area will change by the square of the scale factor, which is , or . Let the surface area of the larger cone be x. Then, the proportion is = . Solve for x and round to the nearest hundredth. The surface area of the larger cone is about inches2.
Mathematics
2 answers:
sveticcg [70]3 years ago
7 0

Answer:

32.61  inches2

edg2020

Step-by-step explanation:

stich3 [128]3 years ago
5 0

Answer:

32.61  inches squared

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Lesechka [4]

Answer:

1.048576e+46

Step-by-step explanation:

(5x5)x20x80 to the power of 10

(25x20)x80 to the power of 10

500x80  to the power of 10

40000 to the power of 10

the answer is 1.048576e+46

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3 years ago
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Step-by-step explanation:

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Yara multiplies and divides a certain number by the same
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For this case we have to:

x: Represents the unknown number

y: Represents the exponent of base 10

So, considering a system of equations we have:

x * 10 ^ y = 40,000\\\frac {x} {10 ^ y} = 0.000004

From the first equation we have:

10 ^ y = \frac {40,000} {x}

Substituting in the second equation:

\frac {x} {\frac {40,000} {x}} = 0.000004\\\frac {x ^ 2} {40,000} = 0.000004\\x ^ 2 = 40,000 * 0.000004\\x ^ 2 = 0.16\\x = \pm \sqrt {0.16}

We choose the positive value:

x = 0.4

So, the number is 0.4.

So:

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Thus, the exponent is 5.

Answer:

Yara use 0.4 and10 ^ 5

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Question 8 Find the unit vector in the direction of (2,-3). Write your answer in component form. Do not approximate any numbers
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Answer:

The unit vector in component form is \hat{u} = \left(\frac{2}{\sqrt{13} },-\frac{3}{\sqrt{13}}  \right) or \hat{u} = \frac{2}{\sqrt{13}}\,i-\frac{3}{13}\,j.

Step-by-step explanation:

Let be \vec u = (2,-3), its unit vector is determined by following expression:

\hat {u} = \frac{\vec u}{\|\vec u \|}

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\|\vec u\|=\sqrt{2^{2}+(-3)^{2}}

\|\vec u\| = \sqrt{13}

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\hat{u} = \frac{1}{\sqrt{13}} \cdot (2,-3)

\hat{u} = \left(\frac{2}{\sqrt{13} },-\frac{3}{\sqrt{13}}  \right)

The unit vector in component form is \hat{u} = \left(\frac{2}{\sqrt{13} },-\frac{3}{\sqrt{13}}  \right) or \hat{u} = \frac{2}{\sqrt{13}}\,i-\frac{3}{13}\,j.

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Making a career decision is simple, and it's not necessary to use a process. true or fralse
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