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kumpel [21]
2 years ago
13

Pls...Solve n + 8 < - 9

Mathematics
2 answers:
dimulka [17.4K]2 years ago
5 0

Answer:

N+8<-9

subtracting 8 in both side

N+8-8<-9-8

N=-17

Sergeeva-Olga [200]2 years ago
5 0

Step-by-step explanation:

n+8<-9

n< -9-8

n<-17 ans

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2 years ago
Equivalent fractions to 1/3
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3 years ago
Line segment GT contains the point G(−3, 5) and a midpoint at A(1, −4). What is the location of endpoint T?
algol [13]

Imagine you're moving along the segment. Since the midpoint is in the middle of the segment (obviously), it means that when you've traveled from G to A, you're halfway through your journey, along both x and y directions. So, let's break the problem in two and analyze both directions.


Along the x axis, you've moved from -3 to 1, so you moved 4 units forward. This means that you have 4 units still to go, and your journey will end at coordinate 5.


Similarly, along the y axis, you've moved from 5 to -4, so you moved 9 units downward. This means that you have 9 units still to go, and your journey will end at coordinate -13.


So, the coordinates of the endpoint are T = (5,-13)


If you prefer a more analyitical approach, simply write the definition of the midpoint and solve it for the coordinates of T.


We have G = (-3, 5) and T = (x_T,y_T). The midpoint is computed as


A = \left( \frac{-3+x_T}{2},\frac{5+y_T}{2} \right) = (1, -4)


So, you have the equations


\frac{-3+x_T}{2} = 1,\qquad \frac{5+y_T}{2} = -4


Multply both equations by 2 to get


-3+x_T = 2,\qquad 5+y_T = -8


Move the constants to the right hand sides to get


x_T = 5,\qquad y_T = -13

8 0
2 years ago
Describe the solutions of 2-5&gt;n in words
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2-5\ \textgreater \ n \ \textgreater \  Switch\;sides \ \textgreater \  n\ \textless \ 2-5 \ \textgreater \  Simplify \ \textgreater \  2-5 \ \textgreater \  -3

n\ \textless \ -3

Hope this helps!
5 0
3 years ago
−2x−x+8= please aswer
shusha [124]

Answer:

-3x+8

Step-by-step explanation:

=-2x+-x+8

=(-2x+-x)+(8)

=-3x+8

5 0
3 years ago
Read 2 more answers
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