Question

A can is 4 inches wide and 8 inches tall. To the nearest whole number, what is the area of a label that wraps around the can if the label is 3 inches shorter than the height of the can? Use 3.14 for pi.

Answer 1

Answer:

The area of a label is $62.8\ in^{2}$

Step-by-step explanation:

we know that

The lateral area of a cylinder (label of the can) is equal to

$LA=2\pi rh$

we have that

A can is 4 inches wide

so

The diameter of the can is 4 inches

$r=4/2=2\ in$ ----> the radius is half the diameter

$h=8-3=5\ in$ ----> height of the label

substitute in the formula

$LA=2(3.14)(2)(5)=62.8\ in^{2}$