Please Solve x2 = 121
2 answers:
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The given function is 
. This is a quadratic function because the degree of the polynomial, the variable with the highest exponent, is 2.
All quadratic functions can be expressed in the form
.
In your equation,
a = -1
b = 50
c = -264
The equation for the x-coordinate vertex of a quadratic function is
.
Applying this to the given function,
.
Now plug the value of x into f(x) to find f(x) (aka the y-coordinate).
The vertex is (25, 361)
Part B
The x-intercept is where the graph crosses the x-axis. Therefore, f(x) (aka the y-coordinate) will be 0. So the x-intercept will be in the form of (x, 0).
To find the x-intercept, set f(x) = 0.
.
Therefore the x-intercepts will be at (6, 0) and (44, 0)
All quadratic functions can be expressed in the form
In your equation,
a = -1
b = 50
c = -264
The equation for the x-coordinate vertex of a quadratic function is
Applying this to the given function,
Now plug the value of x into f(x) to find f(x) (aka the y-coordinate).
The vertex is (25, 361)
Part B
The x-intercept is where the graph crosses the x-axis. Therefore, f(x) (aka the y-coordinate) will be 0. So the x-intercept will be in the form of (x, 0).
To find the x-intercept, set f(x) = 0.
Therefore the x-intercepts will be at (6, 0) and (44, 0)