Answer:
setup below, you'll have to do the final calculation
Step-by-step explanation:
first perform the operation in parenthesis
2+39= 41
then do the multiplication 3 x 41
in general do calculations in this order
1. Parenthesis
2. Multiplication
3. Division
4. Addition
5. Subtraction
working from left to right
It's <span>Diophantine equation.
First, we need to found gcd(6,(-2)):</span>
6=2*3
(-2)=(-1)*2
So, gcd(6,-2)=2
Now, the question is. Can we dived c=24, by gcd(6,-2) and in the end get integer?
Yes we can.

So, we can solve it.
Now is the formula:

Second, we need the first pair (x0,y0)
if
x=0
then

Third, we gonna use that formula:

Congratulations! We solve it.
Answer:
Only 4 is the right answer. The rest all are false.
Answer:
Step-by-step explanation:
2^0 is less than or equal to 1!, because 1<= 1
if 2^n <= (n+1)!, we wish to show that 2^(n+1) <= (n+2)!, since
(n+2)! = (n+1)! * (n+2), and (n+1)!>= 2^n, then we want to prove that n+2<=2, which is always true for n>=0
YES the ordered pair can satisfy the eqaution