1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Bogdan [553]
3 years ago
11

What is the solution to the equation e^3x=12 Round your answer to the nearest hundredth

Mathematics
2 answers:
ch4aika [34]3 years ago
7 0

Answer:

.83 A

Step-by-step explanation:


Lunna [17]3 years ago
3 0

Keywords:

<em>equation, variable, clear, round, centesima, neperian logarithm, exponential </em>

For this case we have the following equation e ^ {3x} = 12, from which we must clear the value of the variable "x" and round to the nearest hundredth. To do this, we must apply properties of neperian and exponential logarithms. By definition:

ln (e ^ x) = x

So:

e ^ {3x} = 12 We apply Neperian logarithm to both sides:

ln (e^{3x}) = ln (12)\\3x = ln (12)

We divide between "3" both sides of the equation:

\frac {3x} {3} = \frac {ln (12)} {3}\\x = \frac {ln (12)} {3}\\x = 0.828302217

Rounding out the nearest hundredth we have:

x = 0.83

Answer:

x = 0.83

You might be interested in
How do you solve for the inequality 4x + 8 &lt; 1+(2x-5).
pishuonlain [190]
Answer:
13 over 2

Step-by-Step equation:

4x + 8<2x - 5
4x - 2x < -5-8
-2x<-13
x>13/2 (13 over 2)
5 0
3 years ago
Quadratic Equations Solve for x. x2+2=102 Enter the solutions for the equation in the boxes.
crimeas [40]
I believe that the equation has X to the 2 power meaning that the answer for X is...
X= 10, and -10
7 0
3 years ago
Read 2 more answers
Nathan Budget $100 for ice tea and spend 10 on ice tea every day. which of the following questions by the amount of money remain
maxonik [38]

you wil have 30$ remaning

Step-by-step explanation:

becuse 100-70 is 30 becuse u spent  10 o ice tea for 1 week and theres 7 days in a week :D

7 0
3 years ago
Rewrite the following equation in slope-intercept form 9x + 7y = -12 please put how to do it too im so confused
Lelechka [254]

Answer:

7y = -9x - 12

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Please help. urgent. calculate the value of: E= x^3+1/x^3 if 1/x+x=4<br>(picture below)
Lelu [443]

Answer:

52

Step-by-step explanation:

1. We see if we cube both sides of the second equation, then it looks more similar to the first equation (E = x^3 + 1/x^3)

(1/x + x)^3 = 4^3

1/x^3 + 3/x + 3x + x^3 = 64

2. Now we rearrange, because we see x^3 + 1/x^3 in the first equation in this equation

x^3 + 1/x^3 + 3x + 3/x = 64

3. We look at 3x + 3/x and see that it looks like the second equation, so we try factoring it

x^3 + 1/x^3 + 3(x + 1/x) = 64

we know x + 1/x = 4, so 3(x + 1/x) = 12

x^3 + 1/x^3 +12 = 64

4. Now we subtract and get our answer

x^3 + 1/x^3 = 52

4 0
3 years ago
Other questions:
  • Determine the transformations done on pentagon 1 to obtain pentagon 2.<br> [[ ANSWER ASAP ]]
    9·1 answer
  • Please help me with number 12!
    15·1 answer
  • How can we check the binomial factors to verify that they are truly factors? Are the factors (x + 5)(x – 8) truly factors of x2
    14·2 answers
  • What is the speed of a 1,500kg car if its kinetic energy is 1,518,750 J?
    13·2 answers
  • Simplify (3n - 2m)^2 = Can someone break this down for me? I don't understand why I'm having issues with this.
    7·2 answers
  • A rectangular prism has a volume of 100 cubic meters. One of the dimensions is 5 meters. Which pair of measurements could be the
    7·1 answer
  • Umm yea solve this....
    14·1 answer
  • Plastic parts produced by an injection-molding operation are checked for conformance to specifications. Each tool contains 15 ca
    14·1 answer
  • ANSWER ONLY IF U KNOW, OR THINK U KNOW.<br><br><br> (ILL MARK U BRAINLIEST)
    11·2 answers
  • For the inequality, find TWO values for x that make the inequality true: 5x&lt;2
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!