Answer:
3/14
Step-by-step explanation:
1st subtract the y's
the subtract the x's in the same order
-9 - 5 = -14
put the first result over the second
-3/-14 = 3/14
= 1/2kx2
U = potential energy of a spring at a certain position
k = the spring constant, specific to the spring, with units N/m.
x = distance the spring is stretched or compressed away from equilibrium
Potential Energy: Elastic Formula Questions:
1) A spring, which has a spring constant k = 7.50 N/m, has been stretched 0.40 m from its equilibrium position. What is the potential energy now stored in the spring?
Answer: The spring has been stretched x = 0.40 m from equilibrium. The potential energy can be found using the formula:
U = 1/2kx2
U = 1/2(7.50 N/m)(0.40 m)2
U = 0.60 N∙m
U = 0.60 J
Answer:
option D is correct
Step-by-step explanation:
Given data
From the given expression/options of answers, option D is correct
This is because the given expression in the attached file corresponds to the terms in option D
Answer:
Step-by-step explanation:
1 side = 2.5y - 3
8 sides = 8(2.5y - 3)
8 sides = 20y - 24
Perimeter = 20y - 24
You need to divide 71 / 10.
